#!/usr/bin/env python2
#-*- coding:utf-8 -*-
__author__ = 'jalright'
"""
use python Implement the perpetual calendar
"""
def is_leap_year(year):
"""
To determine if it is a leap year, return boolean value
"""
if year/4==0 and year/400 !=0:
return True
elif year/100 == 0 and year/400 ==0 :
return True
else:
return False
def getMonthDays(year,month):
"""
Gets the number of days in a given month
"""
days = 31 #31 Most days, set to default
if month == 2 : #2 The month determines whether it is a leap year
if is_leap_year(year):
days=29
else:
days=28;
elif month in [4,6,9,11]: # Judge the month, only 30 day
days=30
return days
def getTotalDays(year,month):
"""
To obtain 1990-01-01 How many days till now, 1990-01-01 It's Monday, and that's the standard for the week
"""
totalDays=0
for i in range(1990,year): # use range So let's do the cycle. Let's figure out how many years and how many days
if is_leap_year(i): # Decide if it's a leap year
totalDays += 366
else:
totalDays += 365
for i in range(1,month): # use range Cycle, and figure out how many days have passed in the first few months of the year
totalDays +=getMonthDays(year,i)
return totalDays
if __name__ == '__main__':
while True: # The loop determines if the format is entered incorrectly
print " X x x x x x x x x x python Achieve calendar ×××××××× "
year = raw_input(" Please enter the year (e.g. : 1990 ) : ")
month = raw_input(" Please enter month: such as: 1")
try: # Capture the correct input exception format and month
year = int(year)
month = int(month)
if month <1 or month >1: # Determine if the month is entered incorrectly, and the error starts the loop again
print " Year or month input error, please re-enter! "
continue
except: # Catches an exception converted to an integer, prints a prompt, and starts the loop again
print " Year or month input error, please re-enter! "
continue
break # If there are no exceptions, break out of the loop
#if is_leap_year(year):
# print "%s Is a leap year "%year
#else:
# print "%s Is a leap year "%year
#print "%s Month total %s Day! "%(month,getMonthDays(year,month))
print " day t one t two t three t four t five t six "
iCount = 0 # A counter to determine if there is a line break
for i in range(getTotalDays(year,month)%7):
print 't', # The output is blank and does not wrap
iCount+=1
for i in range(1,getMonthDays(year,month)):
print i,
print 't',
iCount +=1
if iCount%7 == 0 : # The counter takes the remainder of 0, A newline
print ''