Python implementation of the solar calendar to the lunar calendar (lunar) algorithm
- 2020-04-02 13:36:05
- OfStack
Searching through several python implementations of the almanac, many of which had problems some of the time, most of which came from this code:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
'''
Usage: ccal Month [4-Digit-Year]
or: ccal 4-Digit-Year Month
This Python script is to show Solar and Lunar calender at the
same time. You need to have Python (2.0 or above) installed.
Acceptable date range: 1900/2 -- 2049/12
Output contains Chinese characters (mainland GB2312 encoding),
must be viewed in a Chinese-enabled system or "cxterm" etc.
programms under UNIX X-Windows.
The major reference for me to compose this program is:
lunar-2.1.tgz (1992), composed by
Fung F. Lee <lee@umunhum.stanford.edu> and
Ricky Yeung <Ricky.Yeung@Eng.Sun.Com> .
And Lee and Yeung refered to:
1. "Zhong1guo2 yin1yang2 ri4yue4 dui4zhao4 wan4nian2li4"
by Lin2 Qi3yuan2. Chinese calendar of Yin and Yang, sun and moon. Lin
2. "Ming4li3 ge2xin1 zi3ping2 cui4yan2" by Xu2 Le4wu2.
The theory of numerology. xu
3. Da1zhong4 wan4nian2li4. Universal calendar
License:
GNU General Public License (GPL, see http://www.gnu.org).
In short, users are free to use and distribute this program
in whole. If users make revisions and distribute the revised
one, they are required to keep the revised source accessible
to the public.
Version:
0.3.2, Jan/16/2007, according to sprite's information, changed 3 codes:
1954: 0x0a5d0 --> 0x0a5b0, 1956: 0x052d0 --> 0x052b0
1916: 0x0d6a0 --> 0x056a0
0.3.1, Jan/15/2007, changed 1978's code from 0xb5a0 to 0xb6a0.
A young lady's birth day (lunar 1978/8/4) problem reported
on internet -- informed by sprite at linuxsir.org
0.3.0, Sep/25/2006, add coding line, prevent python to report warning
0.2.0, Jan/6/2002, ShengXiao( Chinese zodiac ), lunar leap month( Leap month )
added.
0.1.0, Jan/4/2002
--- Changsen Xu <xucs007@yahoo.com>
'''
#Remember, in this program:
# month=0 means Januaray, month=1 means February ...;
# day=0 means the first day of a month, day=1 means the second day,
# so as to ease manipulation of Python lists.
# year=0 is 1900, until the last step to output
daysInSolarMonth= [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
lunarMonthDays = [29,30] # a short (long) lunar month has 29 (30) days */
shengXiaoEn = ["Mouse", "Ox", "Tiger", "Rabbit", "Dragon", "Snake",
"Horse", "Goat", "Monkey", "Rooster", "Dog", "Pig"]
shengXiaoGB = [" The rat ", " The cow ", " The tiger ", " The rabbit ", " dragon ", " The snake ", " The horse ", " The sheep ", " The monkey ", " chicken ",
" The dog ", " The pig "]
zhiGB = [" The child ", " The ugly ", " Yin ", " sockets ", " Chen" ", " The third ", " noon ", " not ", " " ", " unitary ",
" xu-gou ", " hai "]
ganGB = [" a ", " b ", " c ", " ding ", " e ", " f ", " heptyl ", " simba ", " nonyl ", " decyl "]
monthEn = ['January', 'February', 'March', 'April', 'May', 'June',
'July', 'August', 'September', 'October', 'November',
'December']
weekdayEn = ["Monday", "Tuesday", "Wednesday", "Thursday",
"Friday", "Saturday", "Sunday"]
weekdayGB = [" one ", " two ", " three ", " four ", " five ", " six ", " day "]
numGB = [' a. ', " one ", " two ", " three ", " four ", " five ", " six ", " seven ", " eight ", " nine ",
" ten "]
lunarHoliday = {'0_0':' Spring Festival ', '4_4':' Dragon Boat Festival ', '7_14':' The Mid-Autumn festival ', '8_8':' chongyang ',
'0_14':' Glutinous Rice Ball for Lantern Festival '}
# encoding:
# b bbbbbbbbbbbb bbbb
# bit# 1 111111000000 0000
# 6 543210987654 3210
# . ............ ....
# month# 000000000111
# M 123456789012 L
#
# b_j = 1 for long month, b_j = 0 for short month
# L is the leap month of the year if 1<=L<=12; NO leap month if L = 0.
# The leap month (if exists) is long one if M = 1.
yearCode = [
0x04bd8, # 1900
0x04ae0, 0x0a570, 0x054d5, 0x0d260, 0x0d950, # 1905
0x16554, 0x056a0, 0x09ad0, 0x055d2, 0x04ae0, # 1910
0x0a5b6, 0x0a4d0, 0x0d250, 0x1d255, 0x0b540, # 1915
0x056a0, 0x0ada2, 0x095b0, 0x14977, 0x04970, # 1920
0x0a4b0, 0x0b4b5, 0x06a50, 0x06d40, 0x1ab54, # 1925
0x02b60, 0x09570, 0x052f2, 0x04970, 0x06566, # 1930
0x0d4a0, 0x0ea50, 0x06e95, 0x05ad0, 0x02b60, # 1935
0x186e3, 0x092e0, 0x1c8d7, 0x0c950, 0x0d4a0, # 1940
0x1d8a6, 0x0b550, 0x056a0, 0x1a5b4, 0x025d0, # 1945
0x092d0, 0x0d2b2, 0x0a950, 0x0b557, 0x06ca0, # 1950
0x0b550, 0x15355, 0x04da0, 0x0a5b0, 0x14573, # 1955
0x052b0, 0x0a9a8, 0x0e950, 0x06aa0, 0x0aea6, # 1960
0x0ab50, 0x04b60, 0x0aae4, 0x0a570, 0x05260, # 1965
0x0f263, 0x0d950, 0x05b57, 0x056a0, 0x096d0, # 1970
0x04dd5, 0x04ad0, 0x0a4d0, 0x0d4d4, 0x0d250, # 1975
0x0d558, 0x0b540, 0x0b6a0, 0x195a6, 0x095b0, # 1980
0x049b0, 0x0a974, 0x0a4b0, 0x0b27a, 0x06a50, # 1985
0x06d40, 0x0af46, 0x0ab60, 0x09570, 0x04af5, # 1990
0x04970, 0x064b0, 0x074a3, 0x0ea50, 0x06b58, # 1995
0x055c0, 0x0ab60, 0x096d5, 0x092e0, 0x0c960, # 2000
0x0d954, 0x0d4a0, 0x0da50, 0x07552, 0x056a0, # 2005
0x0abb7, 0x025d0, 0x092d0, 0x0cab5, 0x0a950, # 2010
0x0b4a0, 0x0baa4, 0x0ad50, 0x055d9, 0x04ba0, # 2015
0x0a5b0, 0x15176, 0x052b0, 0x0a930, 0x07954, # 2020
0x06aa0, 0x0ad50, 0x05b52, 0x04b60, 0x0a6e6, # 2025
0x0a4e0, 0x0d260, 0x0ea65, 0x0d530, 0x05aa0, # 2030
0x076a3, 0x096d0, 0x04bd7, 0x04ad0, 0x0a4d0, # 2035
0x1d0b6, 0x0d250, 0x0d520, 0x0dd45, 0x0b5a0, # 2040
0x056d0, 0x055b2, 0x049b0, 0x0a577, 0x0a4b0, # 2045
0x0aa50, 0x1b255, 0x06d20, 0x0ada0 # 2049
]
yearsCoded = len(yearCode)
from sys import argv, exit, stdout
from time import time, localtime
ow=stdout.write
class LunarYearInfo:
def __init__(self):
self.yearDays = 0
self.monthDays = [0]*13
self.leapMonth = -1 # -1 means no lunar leap month
yearInfo = [0]*yearsCoded #global variable
for i in range(yearsCoded):
yearInfo[i] = LunarYearInfo()
class Date:
def __init__(self, year, month, day, weekday=-1, gan=-1, zhi=-1):
self.year =year
self.month =month
self.day =day
self.weekday=weekday
self.gan =gan
self.zhi =zhi
solar1st = Date(0, 0, 30, weekday=2) #Wednesday, January 31, 1900
lunar1st = Date(0, 0, 0, weekday=2, gan=6, zhi=0)
#Wednesday, First day, First month, 1900, China
def error(msg):
print 'Error:', msg; exit(0)
def isSolarLeapYear (year):
year=year+1900
return (year%4 == 0) and (year%100 != 0) or (year%400 == 0)
baseYear=1201 - 1900
# in fact, real baseYear=1201. In order to ease calculation of
# leap years. real baseYear must conform to:
# realBaseYear%4==1 and realBaseYear%400==1.
# Assert realBaseYear < solar1st.year .
# Compute the number of days from the Solar First Date
# month=0 means January, ...
def solarDaysFromBaseYear(d): #d is a Date class
delta = d.year - baseYear
offset = delta*365 + delta/4 - delta/100 + delta/400
for i in range(d.month):
offset += daysInSolarMonth[i];
if d.month>1 and isSolarLeapYear(d.year):
offset += 1
offset += d.day
## print '___', year, month, day, 'offset=', offset ########
return offset
# Compute the number of days from the Solar First Date
# month=0 means January, ..., year=0 means 1900, ...
def solarDaysFromFirstDate (d): #d is a Date class
return solarDaysFromBaseYear (d) - solarDaysFromBaseYear (solar1st)
def calcLunarDaysPerMonth(iYear):
code = yearCode[iYear]
leapMonth = code&0xf #leapMonth==0 means no lunar leap month
code >>= 4
for iMonth in range(12):
yearInfo[iYear].monthDays[11-iMonth] = lunarMonthDays [code&0x1]
code >>= 1
if leapMonth>0:
yearInfo[iYear].leapMonth = leapMonth-1
yearInfo[iYear].monthDays.insert (leapMonth,
lunarMonthDays [code & 0x1])
def calcAllLunarYearsInfo():
for iYear in range(yearsCoded):
calcLunarDaysPerMonth (iYear)
for iMonth in range(13):
yearInfo[iYear].yearDays += yearInfo[iYear].monthDays[iMonth]
#input dateSolar, return (dateLunar, isLunarMonthOrNot)
def solar2Lunar(d): #d is a Date class
dLunar = Date(-1, -1, -1) #unknown lunar Date class
offset = solarDaysFromFirstDate(d)
dLunar.weekday = (offset + solar1st.weekday)%7
for iYear in range(yearsCoded):
if offset < yearInfo[iYear].yearDays:
dLunar.year = iYear; break
offset -= yearInfo[iYear].yearDays
if dLunar.year == -1: error ("Date out of range.")
dLunar.gan = (dLunar.year + lunar1st.gan) % 10
dLunar.zhi = (dLunar.year + lunar1st.zhi) % 12
for iMonth in range(13):
if offset< yearInfo[dLunar.year].monthDays[iMonth]:
dLunar.month = iMonth; break
offset -= yearInfo[dLunar.year].monthDays[iMonth]
dLunar.day = offset
isLeapMonth=0
if yearInfo[dLunar.year].leapMonth >=0:
if dLunar.month == yearInfo[iYear].leapMonth + 1:
isLeapMonth=1
if dLunar.month > yearInfo[dLunar.year].leapMonth:
dLunar.month -= 1
return (dLunar, isLeapMonth)
def getSolarDaysInMonth (year, month):
if isSolarLeapYear(year) and month==1:
return 29
else: return daysInSolarMonth[month]
def num2GB (num):
if num==10:
return ' ten '
elif num>10 and num<20:
return ' ten ' + numGB[num-10]
tmp=''
while num>10:
tmp = numGB[num%10] + tmp
num = int(num/10)
tmp = numGB[num] + tmp
return tmp
def lunarDate2GB (dLunar, isLeapMonth):
tmp = str(dLunar.month)+'_'+str(dLunar.day)
if lunarHoliday.has_key( tmp ):
return '[0;33;44m%s[0m '% lunarHoliday[tmp] +
' '*(6-len(lunarHoliday[tmp]))
elif dLunar.day==0:
tmp2 = ' A leap '*isLeapMonth + num2GB(dLunar.month+1) +' month '
return '[7m%s[0m' % tmp2 + ' '*(8-len(tmp2))
elif dLunar.day<10:
return ' In the early ' + num2GB(dLunar.day+1)
else:
return num2GB(dLunar.day+1)
def outputCalendar(year, month):
dLunar = Date(-1,-1,-1)
ow ('n The Gregorian calendar %d years %d month ' % (year+1900, month+1) )
for iDay in range( getSolarDaysInMonth(year, month) ):
dSolar = Date(year, month, iDay)
dLunar, isLeapMonth = solar2Lunar (dSolar)
if iDay==0:
ow (' Began in The lunar calendar %s years %s%s month (%s%s years , Born under %s)n' %
( num2GB(dLunar.year+1900), ' A leap '*isLeapMonth,
num2GB(dLunar.month+1),
ganGB [dLunar.gan], zhiGB[dLunar.zhi], shengXiaoGB[dLunar.zhi]
))
ow ('='*74 + 'n')
for i in range(7):
ow ("%3s %2s " % (weekdayEn[i][:3], weekdayGB[i]) )
ow('nn')
for i in range(dLunar.weekday): ow(' '*11)
elif dLunar.weekday==0: ow('n')
ow ( "%2d %-8s" %(iDay+1, lunarDate2GB(dLunar, isLeapMonth) ) )
ow('nn')
def checkArgv (argv):
argc = len(argv)
if argc==1 or argv[1] in ('-h', '--help'):
print __doc__; exit(0)
#in case people input arguments as "4-digit-year month"
if argc==3 and len(argv[1]) == 4 and len(argv[2]) in (1,2):
argv[1], argv[2] = argv[2], argv[1]
#Get month
month=-1
for iMonth in range(12):
if argv[1].lower() == monthEn[iMonth].lower() or
argv[1].lower() == monthEn[iMonth][:3].lower():
month = iMonth+1; break
if month==-1:
month = eval(argv[1])
if month<1 or month>12: error ("Month not within 1--12.")
#Get year
if argc==2: year = localtime(time())[0]
else:
if len(argv[2]) != 4: error ("Year must be 4 digits.")
year = eval(argv[2])
if year<1900 or year>= 1900+yearsCoded or (year==1900 and month==1):
error ("Year must be within %d--%d, excluding 1900/1."
% (1900, 1900 + yearsCoded-1) )
return year-1900, month-1
year, month = checkArgv(argv)
calcAllLunarYearsInfo()
outputCalendar(year, month)
There is also a problem with this (the data of August 1989 is not converted to the lunar calendar)
Looked at several program, found that this does not need any NB algorithm implementation (if there is no such algorithm) can directly implement the Gregorian calendar to the lunar calendar, is recorded the data of a pile of the lunar calendar, and then according to the basic time to calculate and quite a few days, the correctness of all the lunar data determines the correctness of the program.
My classmates gave me a lua program, I tried it, but I didn't find the wrong one, so I gave it to the program directly (directly from lua to python, which was messy).
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import math
def GetDayOf(st):
# The name of the heavenly stem
cTianGan = [" a "," b "," c "," ding "," e "," f "," heptyl "," simba "," nonyl "," decyl "]
# The name of the branch
cDiZhi = [" The child "," The ugly "," Yin "," sockets "," Chen" "," The third "," noon ", " not "," " "," unitary "," xu-gou "," hai "]
# The animal's name
cShuXiang = [" The rat "," The cow "," The tiger "," The rabbit "," dragon "," The snake ", " The horse "," The sheep "," The monkey "," chicken "," The dog "," The pig "]
# Name of the lunar calendar
cDayName =[
"*"," The new moon "," Lunar calendar "," grade "," 4 "," fifth ",
" which "," The seventh "," Eighth day "," The ninth "," The 10th ",
" eleven "," twelve "," thirteen "," fourteen "," fifteen ",
" sixteen "," seventeen "," eighteen "," nineteen "," twenty ",
" 21 "," 22 "," 23 "," 24 "," 25 ",
" 26, "," 27 "," 28 "," 29th "," thirty "
]
# Name of lunar month
cMonName = ["*"," is "," two "," three "," four "," five "," six ", " seven "," eight "," nine "," ten "," eleven "," la "]
# The days preceding each month in the calendar
wMonthAdd = [0,31,59,90,120,151,181,212,243,273,304,334]
# � The lunar data
wNongliData = [2635,333387,1701,1748,267701,694,2391,133423,1175,396438
,3402,3749,331177,1453,694,201326,2350,465197,3221,3402
,400202,2901,1386,267611,605,2349,137515,2709,464533,1738
,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762
,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413
,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395
,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031
,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222
,268949,3402,3493,133973,1386,464219,605,2349,334123,2709
,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877]
# -- take the current Gregorian calendar year, month, day --
wCurYear = st["year"]
wCurMonth = st["mon"]
wCurDay = st["day"]
# -- calculate to initial time 1921 years 2 month 8 Days of days: 1921-2-8( The first day ) -
#nTheDate = (wCurYear � 1921) * 365 + (wCurYear � 1921)/4 + wCurDay + wMonthAdd[wCurMonth] � 38
nTheDate = (wCurYear � 1921) * 365 + (wCurYear � 1921)/4 + wCurDay + wMonthAdd[wCurMonth-1] � 38
if (((wCurYear % 4) == 0) and (wCurMonth > 2)):
nTheDate = nTheDate + 1
# Calculation of the lunar calendar tiangan, di zhi, month, day -
nIsEnd = 0
m = 0
while nIsEnd != 1:
#if wNongliData[m+1] < 4095:
if wNongliData[m] < 4095:
k = 11
else:
k = 12
n = k
while n>=0:
nBit = wNongliData[m]
for i in range(n):
nBit = math.floor(nBit/2);
nBit = nBit % 2
if nTheDate <= (29 + nBit):
nIsEnd = 1
break
nTheDate = nTheDate � 29 � nBit
n = n � 1
if nIsEnd != 0:
break
m = m + 1
wCurYear = 1921 + m
wCurMonth = k � n + 1
wCurDay = int(math.floor(nTheDate))
if k == 12:
if wCurMonth == wNongliData[m] / 65536 + 1:
wCurMonth = 1 � wCurMonth
elif wCurMonth > wNongliData[m] / 65536 + 1:
wCurMonth = wCurMonth � 1
print ' The Gregorian calendar ', st["year"], st["mon"], st["day"]
print ' According to the lunar calendar ', wCurYear, wCurMonth, wCurDay
# The formation of the lunar calendar tiangan, branches, Chinese zodiac ==> wNongli �
szShuXiang = cShuXiang[(((wCurYear - 4) % 60) % 12) + 1]
szShuXiang = cShuXiang[(((wCurYear - 4) % 60) % 12) + 1]
zNongli = szShuXiang + '(' + cTianGan[(((wCurYear - 4) % 60) % 10)] + cDiZhi[(((wCurYear - 4) % 60) % 12)] + ') years '
# � szNongli,"%s(%s%s) years ",szShuXiang,cTianGan[((wCurYear - 4) % 60) % 10],cDiZhi[((wCurYear - 4) % 60) % 12]);
# The Chinese calendar month, day ==> wNongliDay � */
if wCurMonth < 1:
szNongliDay = " A leap " + cMonName[(-1 * wCurMonth)]
else:
szNongliDay = cMonName[wCurMonth]
szNongliDay = szNongliDay + " month " + cDayName[wCurDay]
print szNongliDay
#return szNongli .. szNongliDay
def main():
st = {"year": 1989, "mon": 8, "day": 1}
GetDayOf(st)
st1 = {"year": 2013, "mon": 10, "day": 7}
GetDayOf(st1)
st1 = {"year": 2013, "mon": 10, "day": 1}
GetDayOf(st1)
#print("" .. GetDayOf(st))
main()
The data is basically correct, according to their own needs to change the procedure. Later there is time to change a little bit better.