The Go language calculates the number of days for a specified month
- 2020-05-19 05:00:22
- OfStack
This example shows how the Go language calculates a given number of days per month. Share with you for your reference. The specific implementation method is as follows:
package main
import (
"fmt"
"bufio"
"os"
"regexp"
"strconv"
)
func main() {
year := input("year", "^[0-9]{1}[0-9]{3}$")
month := input("month", "^(0{1}[0-9]{1}|1{1}[0-2]{1})$")
count(year, month)
fmt.Println("Press Enter button to continue ...")
reader := bufio.NewReader(os.Stdin)
lastInput, _, err := reader.ReadRune()
if err != nil {
fmt.Fprintln(os.Stderr, "Occur error when input (last) '", lastInput, "':", err)
}
return
}
func count(year int, month int) (days int) {
if month != 2 {
if month == 4 || month == 6 || month == 9 || month == 11 {
days = 30
} else {
days = 31
fmt.Fprintln(os.Stdout, "The month has 31 days");
}
} else {
if (((year % 4) == 0 && (year % 100) != 0) || (year % 400) == 0) {
days = 29
} else {
days = 28
}
}
fmt.Fprintf(os.Stdout, "The %d-%d has %d days.\n", year, month, days)
return
}
func input(name string, regexpText string) (number int) {
var validNumber = false
for !validNumber {
fmt.Println("Please input a", name, ": ")
reader := bufio.NewReader(os.Stdin)
inputBytes, _, err := reader.ReadLine()
if err != nil {
fmt.Fprintln(os.Stderr, "Occur error when input", name, ":", err)
continue
}
inputText := string(inputBytes)
validNumber, err = regexp.MatchString(regexpText, inputText)
if err != nil {
fmt.Fprintln(os.Stderr, "Occur error when match", name, "(", inputText, "):",err)
continue
}
if validNumber {
number, err = strconv.Atoi(inputText)
if err != nil {
fmt.Fprintln(os.Stderr, "Occur error when convert", name, "(", inputText, "):", err)
continue
}
} else {
fmt.Fprintln(os.Stdout, "The", name, "(", inputText, ") does not have the correct format!")
}
}
fmt.Println("The input", name, ": ", number)
return
}I hope this article has been helpful to your programming of Go language.