Verification of ID card information of Python actual combat small project

python small project-ID card information verification

Purpose

Make a program, input ID number, output the following information

Gender: Male
Area: Yongding County, Longyan City, Fujian Province
Date of birth: May 1, 2000
The first boy registered at the police station on the day of birth
Check code: 0
Authenticity of ID number: true

Required documents and knowledge

ID card area code.xls (uploaded) Composition of ID card number ID card check code algorithm

Check code algorithm

18-digit ID card = 17-digit information data +1-digit check code

1到6位	7到14位	15到16位	17位	18位
区域代码	出生年月日	登记所代码	性别	校验码

Gender: Odd number for boys and even number for girls

1 means the first registered boy
3 means the second registered boy
And so on

Detailed Explanation of Verification Algorithm

1 to 17 bits multiplied by the corresponding weight and summed Take the remainder of the result over 11 Find the corresponding check code according to the remainder

Weights for every 1 bit (17 bits of information data, from left to right, the first bit corresponds to 7, the second bit corresponds to 9, and so on)

weights=[7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2]

Dictionary of remainder and check code correspondence (2 corresponds to Roman numeral "X"-10)

verification_dict={0:1,
                   1:0,
                   2:"X",
                   3:9,
                   4:8,
                   5:7,
                   6:6,
                   7:5,
                   8:4,
                   9:3,
                   10:2}

Complete code presentation (you can do it yourself first)

import pandas as pd
import numpy as np
data = pd.read_excel(' ID card area code full version .xls')

#  Read 18 ID card 
sfz=input()

#  Slicing ID card information 
position=int(sfz[0:6])
birthday=sfz[6:14]
police_code=sfz[14:16]
sex_code=int(sfz[16])
verification=int(sfz[17])

#  Get the name of the area, such as Yongding County, Longyan City, Fujian Province 
position_name=data.iloc[data.loc[data[' Code '] == position].index[0]][' Name ']

#  Determine the gender and determine which one is registered by the registration office 
def sex(n):
    train_list=[]
    male_list=[1,3,5,7,9]
    female_list=[0,2,4,6,8]
    if n in male_list:
        train_list.append(' Male ')
        train_list.append(male_list.index(n)+1)
    else:
        train_list.append(' Female ')
        train_list.append(female_list.index(n)+1)
    return train_list

#  Check algorithm 
weights=[7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2]
sfz_code=[]
for item in sfz:
    sfz_code.append(int(item))
    
weights_sfz=[]

for i in sfz_code:
    for j in weights:
        weights_sfz.append(i*j)

#  Find the remainder 
target=sum(weights_sfz)%11

verification_dict={0:1,
                   1:0,
                   2:"X",
                   3:9,
                   4:8,
                   5:7,
                   6:6,
                   7:5,
                   8:4,
                   9:3,
                   10:2}

#  Find the number corresponding to the remainder 18 Bit check code 
def verification_whether(target_n):
    return verification_dict[target_n]

#  See if the input ID card check code and the calculated check code are 1 To, if not 1 To, it is a fake ID card 
def verification_true_false(sfz_verification,target_n_whether):
    if sfz_verification == target_n_whether:
        return " True "
    else:
        return " Fake "

#  Format and print the results 
print(" Gender       : ",sex(sex_code)[0])
print(" Region       : ",position_name)
print(" Date of birth:  {} Year {} Month {} Day ".format(birthday[0:4],birthday[4:6],birthday[6:8]))
print(" The first place registered by the police station on the day of birth  {}  A {} Child ".format(sex(sex_code)[1],sex(sex_code)[0]))
print(" Check code: ",verification)
print(" Authenticity of ID number: ",verification_true_false(verification,verification_whether(target)))

Talents are shallow, and there are many deficiencies in code. Welcome to exchange and learn!
Jay Kwong