Explanation of python Using Byte Processing File Example

1. You can add the 'b' character to the mode parameter. The same method for all file objects. However, each method expects and returns 1 bytes object.

>>> with open(`dog_breeds.txt`, 'rb') as reader:
>>>     print(reader.readline())
b'Pug\n'

2. When you open the file and read these bytes separately, you can see that it is really an png file:

>>> with open('jack_russell.png', 'rb') as byte_reader:
>>>     print(byte_reader.read(1))
>>>     print(byte_reader.read(3))
>>>     print(byte_reader.read(2))
>>>     print(byte_reader.read(1))
>>>     print(byte_reader.read(1))
b'\x89'
b'PNG'
b'\r\n'
b'\x1a'
b'\n'

Extension of knowledge points:

Read the byte stream data of the file and convert it into 106-ary data

def read_file():
    with open('./flag.zip','rb') as file_byte:
        file_hex = file_byte.read().hex()
        print(file_hex)
        write_file(file_hex)

def write_file(file_hex):
    with open('new.txt','w') as new_file:
        new_file.write(file_hex)

if __name__ == '__main__':
    read_file()

Read the byte stream data of the file, encode it as base64 and output it

import base64

def read_file():
    with open('./flag.zip','rb') as file_byte:
        file_base64 = base64.b64encode(file_byte.read())
        print(file_base64)

if __name__ == '__main__':
    read_file()

Convert 106-ary file into byte stream file to write

import struct

a = open("str.txt","r")#106 Binary data file 
lines = a.read()
res = [lines[i:i+2] for i in range(0,len(lines),2)]

with open("xxx.xxx","wb") as f:
	for i in res:
		s = struct.pack('B',int(i,16))
		f.write(s)

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