Method for python3 to Judge IP Address

In this paper, we share the specific code of python3 to judge IP address for your reference. The specific contents are as follows

Input a string of characters, judge whether the string is a dot-point decimal IP address, if it is converted to hexadecimal output, otherwise output "Error"

Note: The input may be any one string, such as "abc. bas. fefe. 4r4" or "23.23. 11.23. 123"
These are all illegal IP addresses

For example

Input: 192.41. 6.20

Output: 0xC0290614

Input: 257.32. 23.1

Output: Error

Solution 1

import re
def isIP(str):
 p = re.compile('^((25[0-5]|2[0-4]\d|[01]?\d\d?)\.){3}(25[0-5]|2[0-4]\d|[01]?\d\d?)$')
 if p.match(str):
  return True
 # else:
 #  return False
myStr = input()
if isIP(myStr):
 print(IP(myStr).strHex().upper())
 # ip = list(map(int, myStr.split('.')))
 # print('0x', end='')
 # for i in ip:
 #  print(hex(i)[2:].upper().rjust(2, '0'), end='')
else:
 print('Error')

Solution 2:

def change(lis):
 if len(lis)!=4:
 return 'Error'
 try:    #  Determine whether the string has non-numbers 
 lis=[int(i) for i in lis]
 except:
 return 'Error'
 for i in lis:
 if i<0 or i>255: #  Judge ip Is the address legal 
 return 'Error'
 temp='0x'   # Record 16 Binary number 
 for i in lis:
 a=hex(int(i))[2:].upper().rjust(2,'0') # Convert to 16 Binary system 
 # if len(a)!=2:
 # a='0'+a
 temp+=a
 return temp
s=list(map(str,input().split('.')))
print(change(s))

Solution 3

l = input().split(".")
if len(l) != 4:
 print("Error")
else:
 s = ""
 for i in l:
  try:
   num = int(i)
   if num > 255 or num < 0:
    print("Error")
    s = ""
    break
   else:
    s += hex(num)[2:].upper().rjust(2, "0")
  except ValueError:
   print("Error")
   s = ""
   break
 if s:
  print("0x" + s)