python Determines the maximum of three digits instance code

  • 2021-07-26 08:13:02
  • OfStack

python determines the maximum of the three numbers as follows:


# Judge 3 Maximum value in the number 
n1= int(input('please enter the firest number:'))
n2 = int(input('please enter the second number:'))
n3 = int(input('please enter the third number:'))
max_num = 0
if n1 > n2:
 max_num = n1
 if n1 > n3:
  max_num = n1
 else:
  max_num = n3
else:
 max_num = n2
 if n2 > n3:
  max_num = n2
 else:
  max_num = n3
print('the max_num is : %d'%max_num)
'''
if n1>n2:
 max_num = n1
 if max_num > n3:
  print('the max_num is n1')
 else:
  print('the max_num is n3')
else:
 max_num = n2
 if max_num > n3:
  print('the max_num is n2')
 else:
  print('the max_num is n3')
'''

PS: The 3-entry operator of python finds the maximum of 3 numbers

Python

First write a that compares the sizes of two numbers


a = 1
b = 2
max_ = a if a > b else b
print(max_)

Comparison of 3 numbers


num1 = int(input(" Enter the 1 Number: "))
num2 = int(input(" Enter the 2 Number: "))
num3 = int(input(" Enter the 3 Number: "))
max_ = (num1 if num1 > num2 else num2) if(num1 if num1 > num2 else num2) > num3 else num3
print(max_)

Java Empire


package com.zzti.edu;

import java.util.Scanner;

/**
 * @Classname threeEye
 * @Description TODO
 * @Author jdq8576
 * @Date 2019/3/2 14:28
 * @Version 1.0
 **/
public class threeEye {
 public static void main(String[] args){
  int a;
  int b;
  int c;
  Scanner scanner = new Scanner(System.in);
  a = scanner.nextInt();
  b = scanner.nextInt();
  c = scanner.nextInt();
  scanner.close();
  System.out.println((a>b?a:b)>c?(a>b?a:b):c);
 }
}

C++


#include<iostream>
using namespace std;
int main(){
 int a,b,c;
 cin>>a>>b>>c;
 int max = (a>b?a:b)>c?(a>b?a:b):c;
 cout<<max<<endl;
 return 0;
}

Summarize


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