python Determines the maximum of three digits instance code
- 2021-07-26 08:13:02
- OfStack
python determines the maximum of the three numbers as follows:
# Judge 3 Maximum value in the number
n1= int(input('please enter the firest number:'))
n2 = int(input('please enter the second number:'))
n3 = int(input('please enter the third number:'))
max_num = 0
if n1 > n2:
max_num = n1
if n1 > n3:
max_num = n1
else:
max_num = n3
else:
max_num = n2
if n2 > n3:
max_num = n2
else:
max_num = n3
print('the max_num is : %d'%max_num)
'''
if n1>n2:
max_num = n1
if max_num > n3:
print('the max_num is n1')
else:
print('the max_num is n3')
else:
max_num = n2
if max_num > n3:
print('the max_num is n2')
else:
print('the max_num is n3')
'''
PS: The 3-entry operator of python finds the maximum of 3 numbers
Python
First write a that compares the sizes of two numbers
a = 1
b = 2
max_ = a if a > b else b
print(max_)
Comparison of 3 numbers
num1 = int(input(" Enter the 1 Number: "))
num2 = int(input(" Enter the 2 Number: "))
num3 = int(input(" Enter the 3 Number: "))
max_ = (num1 if num1 > num2 else num2) if(num1 if num1 > num2 else num2) > num3 else num3
print(max_)
Java Empire
package com.zzti.edu;
import java.util.Scanner;
/**
* @Classname threeEye
* @Description TODO
* @Author jdq8576
* @Date 2019/3/2 14:28
* @Version 1.0
**/
public class threeEye {
public static void main(String[] args){
int a;
int b;
int c;
Scanner scanner = new Scanner(System.in);
a = scanner.nextInt();
b = scanner.nextInt();
c = scanner.nextInt();
scanner.close();
System.out.println((a>b?a:b)>c?(a>b?a:b):c);
}
}
C++
#include<iostream>
using namespace std;
int main(){
int a,b,c;
cin>>a>>b>>c;
int max = (a>b?a:b)>c?(a>b?a:b):c;
cout<<max<<endl;
return 0;
}
Summarize