How to get the index of a list in python

1. index method

list_a= [12,213,22,2,32]
for a in list_a:
  print(list_a.index(a))

Results: 0 1 2 3 4

If there are no duplicates in the list, then index is fine. What if there are duplicates in the list?

list_a= [12,213,22,2,2,22,2,2,32]
for a in list_a:
  print(list_a.index(a))

Results: 0 1 2 3 3 2 3 3 8 < br > < br >

Obviously, the result is not what you want! ! ! So let's look at the second method >

2. enumerate method, which tuples elements in the list

list_a= [12,213,22,2,2,22,2,2,32]
print(list(enumerate(list_a))) 

Results:

[(0, 12), (1, 213), (2, 22), (3, 2), (4, 2), (5, 22), (6, 2), (7, 2), (8, 32)]

This solves the problem of duplicate elements in the list,

ps: The following python returns the index of a value in the list

list = [5,6,7,9,1,4,3,2,10]
list.index(9)
out:3

You can also return the index of the maximum value in the list list.index(max(list))

Minimum value index list.index(min(list))

Summarize