Must the statement after return in the python function not execute？

preface

The return statement is used to exit a function and return an expression to the caller. return returns None by default without arguments (or without return statements written). None is a special value whose data type is NoneType. NoneType is a special type of Python, which has only one value None.

It doesn't support any operations or built-in methods, always returns false when comparing it to any other data type, and can assign None to any variable...

1. When return is not explicit, None is returned by default

>>> def fun(): 
 print 'ok' 
 
>>> res=fun() 
ok 
>>> type(res) 
<type 'NoneType'> 
>>> res==None 
True 
>>> def func(): 
 print 98 
 return 
 
>>> f=func() 
98 
>>> f 
>>> type(f) 
<type 'NoneType'> 
>>> f==None 
True 

2 always returns false when comparing equality with any other data type

>>> 'python'==None 
False 
>>> ''==None 
False 
>>> 9==None 
False 
>>> 0.0==None 
False 

3) When the return statement is executed, the function will exit and the statement after return will no longer be executed. An exception is to place the return statement in the try block.

def fun(): 
 print 98 
 return 'ok'# Perform to the return Statement, the function terminates and subsequent statements are no longer executed  
 print 98 
 
def func(): 
 try: 
  print 98 
  return 'ok' # I get the function 1 A return value  
 finally:#finally The statements in the statement block are still executed  
  print 98 
 
print fun() 
print '----------' 
print func() 

Operation results:

98
ok
----------
98
98
ok

conclusion