Tkinter based on python writing login registration interface

tkinter created the login and registration interface for your reference, the specific content is as follows

import tkinter as tk
from tkinter import messagebox
 
# Center the window 
def window_info():
 ws = window.winfo_screenwidth()
 hs = window.winfo_screenheight()
 x = (ws / 2) - 200
 y = (hs / 2) - 200
 print("%d,%d" % (ws, hs))
 return x,y
 
# Set the login window properties 
window = tk.Tk()
window.title(' Welcome to the parking fee system ')
a,b=window_info()
window.geometry("450x300+%d+%d"%(a,b))
 
# Login interface information 
tk.Label(window,text=" Carpark charging system ",font=(" Song typeface ",32)).place(x=80,y=50)
tk.Label(window,text=" Account: ").place(x=120,y=150)
tk.Label(window,text=" Password: ").place(x=120,y=190)
# Display input box 
var_usr_name = tk.StringVar()
# Display default account 
var_usr_name.set('1400370101')
entry_usr_name=tk.Entry(window,textvariable=var_usr_name)
entry_usr_name.place(x=190,y=150)
var_usr_pwd = tk.StringVar()
# Display after setting input password * No. 
entry_usr_pwd = tk.Entry(window,textvariable=var_usr_pwd,show='*')
entry_usr_pwd.place(x=190,y=190)
 
# Log in function 
def usr_login():
 # Get the password for the entered account 
 usr_name = var_usr_name.get()
 usr_pwd = var_usr_pwd.get()
 # Get the stored account information, using the database here, call the database query function, but also can use other ways, such as files 
 dicts = SQL.load('login')
 print(dicts)
 bool = False
 for row in dicts:
 print(row.get("name"))
 if usr_name == row["name"]:
  bool = True
  pwd = row["password"]
  print(row)
 if bool == True:
 if usr_pwd == pwd:
  tk.messagebox.showinfo(title='Welcome', message='How are you?' +usr_name)
  mainwindow()
 else:
  tk.messagebox.showerror(message=' Sorry, input error, please try again! ')
 else:
 is_sign_up = tk.messagebox.askyesno('Welcome', ' You haven't registered yet. Should you register now? ')
 if is_sign_up:
  usr_sign_up()
# Registered account 
def usr_sign_up():
 def sign_to_Pyhon():
 np = new_pwd.get()
 npc = new_pwd_confirm.get()
 nn = new_name.get()
 
 dicts = SQL.load('login')
 print(dicts)
 bool = False
 for row in dicts:
  if nn == row["name"]:
  bool = True
  print(row)
 if np!=npc:
  tk.messagebox.showerror(' I'm sorry ',' The password is not entered twice 1 Cause! ')
 elif bool:
  tk.messagebox.showerror((' I'm sorry ',' This account already exists !'))
 else:
  try:
  SQL.insert_login(str(nn),str(np))
  tk.messagebox.showinfo('Welcome',' You have registered successfully! ')
  except:
  tk.messagebox.showerror((' Registration failed !'))
  window_sign_up.destroy()
 # create top The window ACTS as a registration window 
 window_sign_up = tk.Toplevel(window)
 window_sign_up.geometry('350x200')
 window_sign_up.title(' registered ')
 
 new_name = tk.StringVar()
 new_name.set('1400370115')
 tk.Label(window_sign_up,text=' account :').place(x=80,y=10)
 entry_new_name = tk.Entry(window_sign_up,textvariable=new_name)
 entry_new_name.place(x=150,y=10)
 
 new_pwd = tk.StringVar()
 tk.Label(window_sign_up, text=' password :').place(x=80, y=50)
 entry_usr_pwd = tk.Entry(window_sign_up,textvariable=new_pwd,show='*')
 entry_usr_pwd.place(x=150, y=50)
 
 new_pwd_confirm = tk.StringVar()
 tk.Label(window_sign_up,text=' Input again :').place(x=80,y=90)
 entry_usr_pwd_again = tk.Entry(window_sign_up,textvariable=new_pwd_confirm,show='*')
 entry_usr_pwd_again.place(x=150, y=90)
 
 btn_again_sign_up = tk.Button(window_sign_up,text=' registered ',command=sign_to_Pyhon)
 btn_again_sign_up.place(x=160,y=130)
 
# Login and register buttons 
btn_login = tk.Button(window,text=" landing ",command=usr_login)
btn_login.place(x=170,y=230)
btn_sign_up = tk.Button(window,text=" registered ",command=usr_sign_up)
btn_sign_up.place(x=270,y=230)
 
window.mainloop()

This is the login and registration interface I wrote, using tkinter, you can achieve simple login and registration account, using Label, Entry and Button components.