Detailed discussion based on Python3 comma code and character graph grid of

The comma code

Suppose you have the following list:

spam=['apples','bananas','tofu',' cats']

Write a function that takes a list value as an argument and returns a string. The string contains all table entries, separated by commas and Spaces, and inserts and before the last one. For example, the preceding spam list passed to a function, returns' apples, bananas tofu, and cats '. But your function should be able to pass to any list it has.

The code is as follows:

import copy 
 
def conFun(nameList): 
  n=len(nameList) 
  newList=copy.copy(nameList) 
  newList.insert(n-1,'and') 
  # print(newList) 
  a=str(newList.pop()) 
  b=str(newList.pop()) 
  c='' 
  c=b+' '+a 
  newOne='' 
  newOne=newList[0] 
  i=1 
  for j in newList: 
    newOne=newOne+','+newList[i] 
    i=i+1 
    if i==len(newList): 
      break     
  print(newOne+','+c) 

Verification code:

================== RESTART: /Users/valen/Documents/test.py ================== 
>>> spam=['apple','bananas','tofu','cats'] 
>>> conFun(spam) 
apple,bananas,tofu,and cats 
>>>  

Character graph grid

Suppose there is a list of lists, and each value of the inner list is a 1-character string, like this:

grid = [ ['.', '.', '.', '.', '.','.'], 
     ['.', '0', '0', '.', '.','.'], 
     ['0', '0', '0', '0', '.','.'], 
     ['0', '0', '0', '0', '0','.'], 
     ['.', '0', '0', '0', '0','0'], 
     ['0', '0', '0', '0', '0','.'], 
     ['0', '0', '0', '0', '.','.'], 
     ['.', '0', '0', '.', '.','.'], 
     ['.', '.', '.', '.', '.','.']] 

You can think of grid[x][y] as the character of 1 "graph" at the x,y coordinates. The graph consists of text characters. At the origin (0,0) in the upper left corner, the x coordinates increase to the right, and the y coordinates increase to the downward.

Copy the previous grid value and write code to print the image using it.

..OO.OO.. 
.OOOOOOO. 
.OOOOOOO. 
..OOOOO.. 
...OOO... 
....O.... 

Tip: You need to use nested loops, print out grid[0][0], then grid[1][0], then grid[2][1], and so on, until grid[8][0]. This completes line 1, so the next step is to print a newline. The program will then print grid[0][1], then grid[1][1], then grid[2][1], and so on. The program will print grid[8][5] at the end.

Also, if you don't want to automatically print line breaks after every call to print(), remember to pass the end keyword argument to print().

import copy 
 
grid = [ ['.', '.', '.', '.', '.','.'], 
     ['.', '0', '0', '.', '.','.'], 
     ['0', '0', '0', '0', '.','.'], 
     ['0', '0', '0', '0', '0','.'], 
     ['.', '0', '0', '0', '0','0'], 
     ['0', '0', '0', '0', '0','.'], 
     ['0', '0', '0', '0', '.','.'], 
     ['.', '0', '0', '.', '.','.'], 
     ['.', '.', '.', '.', '.','.']] 
c=[] 
c=copy.deepcopy(grid) 
#print(c) 
gridLen=len(grid) 
cyctime=len(grid[0]) 
#print(cyctime)  
i=0 
j=0 
for j in range(cyctime): 
  if j < cyctime : 
    for i in range(gridLen): 
      if i < gridLen : 
        print(c[i][j],end=' ') 
        i=i+1 
  print('\n') 
  j=j+1 

The output is as follows:

================== RESTART: /Users/valen/Documents/test.py ================== 
. . 0 0 . 0 0 . .  
 
. 0 0 0 0 0 0 0 .  
 
. 0 0 0 0 0 0 0 .  
 
. . 0 0 0 0 0 . .  
 
. . . 0 0 0 . . .  
 
. . . . 0 . . . .  
 
>>>