Python gets the current path implementation code

Python gets the current path implementation code

import os,sys

Use sys.path [0], sys.argv [0], os.getcwd (), os.path.abspath (), os.path.realpath ()

sys.path is the list of search paths that Python will find for the module, sys.path [0] and sys.argv [0] are one thing because Python automatically adds sys.argv [0]

sys path.

If you execute python getpath\ getpath.py in the C:\test directory, os.getcwd () will print "C:\test", sys.path [0] will print "C:\test\getpath".

If you compile the Python script into an executable using the py2exe module, the output of sys.path [0] will also change:

If you package the dependent library as an zip file by default, sys.path [0] will output "C:\test\getpath\ libarary.zip";

If the zipfile=None parameter is specified in setup.py and the dependent library is packed into the exe file, sys.path [0] will output "C:\test\getpath\ getpath.exe".

#!/bin/env python
#-*- encoding=utf8 -*-

import os,sys

if __name__=="__main__":

  print "__file__=%s" % __file__

  print "os.path.realpath(__file__)=%s" % os.path.realpath(__file__)

  print "os.path.dirname(os.path.realpath(__file__))=%s" % os.path.dirname(os.path.realpath(__file__))
　　
  print "os.path.split(os.path.realpath(__file__))=%s" % os.path.split(os.path.realpath(__file__))[0]　　

  print "os.path.abspath(__file__)=%s" % os.path.abspath(__file__)

  print "os.getcwd()=%s" % os.getcwd()

  print "sys.path[0]=%s" % sys.path[0]

  print "sys.argv[0]=%s" % sys.argv[0]

Output results:

D:\>python ./python_test/test_path.py
__file__=./python_test/test_path.py
os.path.realpath(__file__)=D:\python_test\test_path.py
os.path.dirname(os.path.realpath(__file__))=D:\python_test
os.path.split(os.path.realpath(__file__))=D:\python_test
os.path.abspath(__file__)=D:\python_test\test_path.py
os.getcwd()=D:\
sys.path[0]=D:\python_test
sys.argv[0]=./python_test/test_path.py

os.getcwd () "D:\" takes the initial execution directory

sys.path [0] or sys.argv [0] "D:\python_test" takes the directory where the script was initially executed

os.path.split (os.path.realpath :\python_test)[0] "D:\python_test", take the directory of the file test_path.py which is located with s 121en__

Get the current path correctly:

__file__ Is the currently executing file 

 

  #  Get the current file __file__ The path of the 

  print "os.path.realpath(__file__)=%s" % os.path.realpath(__file__)

  #  Get the current file __file__ Where directory 

  print "os.path.dirname(os.path.realpath(__file__))=%s" % os.path.dirname(os.path.realpath(__file__)) 　　
  #  Get the current file __file__ Where directory 

  print "os.path.split(os.path.realpath(__file__))=%s" % os.path.split(os.path.realpath(__file__))[0]　

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