# Python programming implements the method of entering a date of a year to calculate the date of that year

• 2020-05-30 20:29:14
• OfStack

This example shows how the programming implementation of Python inputs a date of a year to calculate the date of that year. I will share it with you for your reference as follows:

# based on Python3

1 way:

def is_leap_year(year): #  A leap year is returned True Otherwise return False
if (year % 4 == 0 and year % 100 != 0) or year % 400 == 0:
return True
else:
return False
def function1(year, month, day): #  Calculate the given date to be that 1 The day of the year
leap_year = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
no_leap_year = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
if is_leap_year(year):
result = sum(leap_year[:month - 1]) + day
else:
result = sum(no_leap_year[:month - 1]) + day
return result

But if you're the one with the need, it doesn't have to be that complicated. That's because Python has built-in built-in time and date handling functions.

import datetime
import time
def function2(year, month, day): #  Direct use of Python Built-in module datetime Format conversion function to get results
date = datetime.date(year, month, day)
return date.strftime('%j')

It is important to note that in the above method, the parameters of the function are integers of year, month and day. If you want to pass in a string, such as "2016-10-1", you need to do something with the string first.

Likewise, you can do it yourself or with built-in functions.

#  Suppose the input format is a string (read a string from the command line, for example) 2016-10-1 ), the input needs to be processed first
_input = '2016-10-1'
_year1 = int(_input.split('-')[0])
_month1 = int(_input.split('-')[1])
_day1 = int(_input.split('-')[2])
#  You can use it, too datetime Is a built-in method for formatting
t = time.strptime(_input, '%Y-%m-%d')
_year2 = t.tm_year
_month2 = t.tm_mon
_day2 = t.tm_mday

Below is the complete code. The results of "2016-10-1" are 275.

import datetime
import time
def is_leap_year(year): #  A leap year is returned True Otherwise return False
if (year % 4 == 0 and year % 100 != 0) or year % 400 == 0:
return True
else:
return False
def function1(year, month, day): #  Calculate the given date to be that 1 The day of the year
leap_year = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
no_leap_year = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
if is_leap_year(year):
result = sum(leap_year[:month - 1]) + day
else:
result = sum(no_leap_year[:month - 1]) + day
return result
def function2(year, month, day): #  Direct use of Python Built-in module datetime Format conversion function to get results
date = datetime.date(year, month, day)
return date.strftime('%j')
print(function1(2016, 10, 1))
print(function2(2016, 10, 1))
#  Suppose the input format is a string (read a string from the command line, for example) 2016-10-1 ), the input needs to be processed first
_input = '2016-10-1'
_split = _input.split('-')
_year1 = int(_split[0])
_month1 = int(_split[1])
_day1 = int(_split[2])
print(function1(_year1, _month1, _day1))
print(function2(_year1, _month1, _day1))
#  You can use it, too datetime Is a built-in method for formatting
t = time.strptime(_input, '%Y-%m-%d')
_year2 = t.tm_year
_month2 = t.tm_mon
_day2 = t.tm_mday
print(function1(_year2, _month2, _day2))
print(function2(_year2, _month2, _day2))

#  It turns out that I'm getting a little bit more complicated for function writing, if the input is actually a string 1 A few words is good
import time
_input = '2016-10-1'
#  As shown in the Python The date and string formats are converted to each other  https://www.ofstack.com/article/66019.htm
t = time.strptime(_input, '%Y-%m-%d')
print(time.strftime('%j',t))

PS: here are some other online tools for calculating dates and days:

Online date/days calculator:
http://tools.ofstack.com/jisuanqi/date_jisuanqi

Online calendar:
http://tools.ofstack.com/bianmin/wannianli

Online lunar/solar calendar conversion tool:
http://tools.ofstack.com/bianmin/yinli2yangli

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