Python+Selenium automates paging (pagination) processing

scenario

For pagination, we are most interested in the following information

How many pages are there altogether
What is the current page number
Can I go up to page 1 and down to page 1

code

The following code shows how to get the total number of pages and the current number of pages to jump to the specified number of pages

#coding:utf-8
from selenium import webdriver
import time
driver = webdriver.Chrome()
driver.get("https://segmentfault.com/news")

#  Gets the number of all pages 
# -2 Because you want to get rid of it 1 A and the 1 a 
total_pages = len(driver.find_element_by_class_name("pagination").find_elements_by_tag_name("li"))-2
print "total_pages is %s" %(total_pages)

#  Gets the current page number 
current_page = driver.find_element_by_class_name('pagination').find_element_by_class_name('active')
print "current page is %s" %(current_page.text)

# Jump to the first 2 page 
next_page = driver.find_element_by_class_name("pagination").find_element_by_link_text("2")
next_page.click()