Summary of methods for quickly performing multiple character substitutions in python

First, give the conclusion:

The number of characters to replace is small and can be chained directly replace() The method can be replaced with high efficiency.
If you have a large number of characters to replace, it is recommended to call in the for loop replace() Make the substitution.

Possible methods:

1. Chain replace ()

string.replace().replace()

1. x in for Call in loop replace() "When there are too many characters to replace"

2. Use string. maketrans

re.compile. re.sub

...

def a(text):
 chars = "&#"
 for c in chars:
 text = text.replace(c, "\\" + c)
def b(text):
 for ch in ['&','#']:
 if ch in text:
  text = text.replace(ch,"\\"+ch)
import re
def c(text):
 rx = re.compile('([&#])')
 text = rx.sub(r'\\\1', text)
RX = re.compile('([&#])')
def d(text):
 text = RX.sub(r'\\\1', text)
def mk_esc(esc_chars):
 return lambda s: ''.join(['\\' + c if c in esc_chars else c for c in s])
esc = mk_esc('&#')
def e(text):
 esc(text)
def f(text):
 text = text.replace('&', '\&').replace('#', '\#')
def g(text):
 replacements = {"&": "\&", "#": "\#"}
 text = "".join([replacements.get(c, c) for c in text])
def h(text):
 text = text.replace('&', r'\&')
 text = text.replace('#', r'\#')
def i(text):
 text = text.replace('&', r'\&').replace('#', r'\#')

Reference:

http://stackoverflow.com/questions/3411771/multiple-character-replace-with-python

http://stackoverflow.com/questions/6116978/python-replace-multiple-strings

http://stackoverflow.com/questions/8687018/python-string-replace-two-things-at-once

http://stackoverflow.com/questions/28775049/most-efficient-way-to-replace-multiple-characters-in-a-string

conclusion

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