Python built in function dir
- 2020-05-09 18:49:10
- OfStack
1. Command introduction
Recently, I learned and used one of python's built-in functions, dir. First, help1:
>>> help(dir)
Help on built-in function dir in module __builtin__:
dir()
dir([object]) -> list of strings
Return an alphabetized list of names comprising (some of) the attributes
of the given object, and of attributes reachable from it:
No argument: the names in the current scope.
Module object: the module attributes.
Type or class object: its attributes, and recursively the attributes of
its bases.
Otherwise: its attributes, its class's attributes, and recursively the
attributes of its class's base classes.
With help, you can simply think of dir as listing the properties of a specified object or class.
Example 2.
Here's a simple test:
class A:
def a(self):
pass
class A1(A):
def a1(self):
pass
if __name__ == '__main__':
print("dir without arguments:", dir())
print("dir class A:", dir(A))
print("dir class A1:", dir(A1))
a = A1()
print("dir object a(A1):", dir(a))
print("dir function a.a:", dir(a.a))
Test results:
dir without arguments: ['A', 'A1', '__builtins__', '__doc__', '__file__', '__name__', '__package__']
dir class A: ['__class__', '__delattr__', '__dict__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__le__', '__lt__', '__module__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'a']
dir class A1: ['__class__', '__delattr__', '__dict__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__le__', '__lt__', '__module__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'a', 'a1']
dir object a(A1): ['__class__', '__delattr__', '__dict__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__le__', '__lt__', '__module__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'a', 'a1']
dir function a.a: ['__call__', '__class__', '__delattr__', '__doc__', '__eq__', '__format__', '__func__', '__ge__', '__get__', '__getattribute__', '__gt__', '__hash__', '__init__', '__le__', '__lt__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__self__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__']
3. Use dir to find all the classes under module
The original intention of using this function is to find the class name of the implementation in 1 module, which can be easily implemented through this function.
For example, save the above test program as A.py, and then build another test program. The content is as follows:
import A
if __name__ == '__main__':
print("dir module A:", dir(A))
The results are as follows:
dir module A: ['A', 'A1', '__builtins__', '__doc__', '__file__', '__name__', '__package__']
You can see that both class A and A1 can be found.
4. How to find the class under the current module
This is a problem that has been bothering for a long time, and no detailed solution has been found. The following is my centralized implementation method.
Method 1: called directly under module
For example, if you add 1 line at the bottom of A.py above, you can use selfDir to find the current module class in the following code. The modified code is as follows:
class A:
def a(self):
pass
class A1(A):
def a1(self):
pass
curModuleDir=dir() # get dir of current file(module)
if __name__ == '__main__':
print("dir without arguments:", dir())
print("dir class A:", dir(A))
print("dir class A1:", dir(A1))
a = A1()
print("dir object a(A1):", dir(a))
print("dir function a.a:", dir(a.a))
print("dir current file:", curModuleDir)
4.2. Method 2: import current module
Reference the current module and other import1 samples, the code is as follows:
# A.py
import A as this # import current module
class A:
def a(self):
pass
class A1(A):
def a1(self):
pass
if __name__ == '__main__':
print("dir without arguments:", dir())
print("dir class A:", dir(A))
print("dir class A1:", dir(A1))
a = A1()
print("dir object a(A1):", dir(a))
print("dir function a.a:", dir(a.a))
print("dir current file:", dir(this))
Method 3: look up module by module name, then call dir
We know that there is a property below module showing the module name, how can we find the module object according to the module name? You can use sys.modules. The code is as follows:
import sys
class A:
def a(self):
pass
class A1(A):
def a1(self):
pass
if __name__ == '__main__':
print("dir without arguments:", dir())
print("dir class A:", dir(A))
print("dir class A1:", dir(A1))
a = A1()
print("dir object a(A1):", dir(a))
print("dir function a.a:", dir(a.a))
print("dir current file:", dir(sys.modules[__name__])) # use __name__ Gets the current module Object, which is then obtained using the object dir