The Python implementation generates a simple code sample for the Makefile file

Write a few test programs under Linux and type g++ command line by line to compile. When you frequently change the test code, the repeated typing (or on-line arrow selection again and again) is not as good as the speed of make. The advantage of using a Makefile goes without saying. Here I've written a script that automatically searches for ".c "files in the current directory (not including subdirectories) to generate makefiles.

In this case, the code has limited functionality (in cases where a single file is a separate test code), and those who need it can make minor modifications to meet the requirements.

#! /usr/bin/python

'''

 File      : genMakefile.py

 Author    : Mike

 E-Mail    : Mike_Zhang@live.com

'''

import os
def genMakefileStr(dir,surfix = '.c'):

    msg = ''

    msg = msg + 'CC = gcc' + 'n'

    msg = msg +  'CFLAGS = -g -O2 -Wall' + 'nn'

    

    fList = []

    for dirPath,dirNames,fileNames in os.walk(dir):

        for file in fileNames:

            name,extension = os.path.splitext(file)

            if extension == surfix:

                fList.append(name)

        break # only search the current directory

    str1 = 'all:n'

    str2 = ''

    str3 = 'clean:n'

    for f in fList:

        str1 = str1 + 'tmake ' + f + 'n'

        str2 = ('%s%s:%s.on') % (str2,f,f)

        str2 = ('%st$(CC) -o %s %s.onn') % (str2,f,f)

        str3 = ('%strm -f %sn') % (str3,f)

    str3 = str3 + 'trm -f *.on'

    strClean = '.c.o:nt$(CC) $(CFLAGS) -c -o $*.o $<n'

    msg = ('%s%sn%sn%sn%s') % (msg,str1,str2,str3,strClean) 

    #print 'msg : n'

    #print msg

    return msg
if __name__ == '__main__':

    str = genMakefileStr('.','.c')

    file = open("Makefile","w")

    file.write(str)

    file.close()

    print str

The operation effect is as follows (example) :

# ./genMakefile.py          

CC = gcc

CFLAGS = -g -O2 -Wall
all:

        make pfun1

        make pfun2
pfun1:pfun1.o

        $(CC) -o pfun1 pfun1.o
pfun2:pfun2.o

        $(CC) -o pfun2 pfun2.o


clean:

        rm -f pfun1

        rm -f pfun2

        rm -f *.o
.c.o:

        $(CC) $(CFLAGS) -c -o $*.o $<

Just make after you run the script.

The attached:

I feel that the above script is not convenient to use, and then I modify it. The code is as follows:

#! /usr/bin/python

'''

  File      : genMakefile.py

  Author    : Mike

  E-Mail    : Mike_Zhang@live.com

'''

import os,sys

 

surfix = ['.c','.cpp']
def genMakefileStr(dir):

    msg = ''

    msg = msg + 'CC = g++ ' + 'n'

    msg = msg +  'CFLAGS = -g -O2 -Wall' + 'nn'

    

    fList = []

    for dirPath,dirNames,fileNames in os.walk(dir):

        for file in fileNames:

            name,extension = os.path.splitext(file)

            if surfix.count(extension) > 0:

                fList.append(name)

        break # only search the current directory

    str1 = 'all:n'

    str2 = ''

    str3 = 'clean:n'

    for f in fList:

        str1 = str1 + 'tmake ' + f + 'n'

        str2 = ('%s%s:%s.on') % (str2,f,f)

        str2 = ('%st$(CC) -o %s %s.onn') % (str2,f,f)

        str3 = ('%strm -f %sn') % (str3,f)

    str3 = str3 + 'trm -f *.on'

    strClean = '.c.cpp.o:nt$(CC) $(CFLAGS) -c -o $*.o $<n'

    msg = ('%s%sn%sn%sn%s') % (msg,str1,str2,str3,strClean) 

    #print 'msg : n'

    #print msg

    return msg

 

if __name__ == '__main__':

    for arg in sys.argv[1:]:

        print arg

    str = genMakefileStr(arg)

    if arg[-1] == '/':arg = arg[:-1]

    file = open(arg+"/Makefile","w")

    file.write(str)

    file.close()

    print str

Change the file genmakefile.py to genMakefile, copy it to /usr/local/bin, and then execute the following command in the required directory:

GenMakefile.