Examples of common date and time handling methods in Python

  • 2020-04-02 14:32:53
  • OfStack

#-*- coding: utf-8 -*-
import datetime


# Given date backward N The date of the day 
def dateadd_day(days):
  d1 = datetime.datetime.now()
  d3 = d1 + datetime.timedelta(days)
  return d3


# Yesterday, 
def getYesterday():
  today = datetime.date.today()
  oneday = datetime.timedelta(days=1)
  yesterday = today - oneday
  return yesterday


# Today, 
def getToday():
  return datetime.date.today()


# Gets the date of the last few days for a given parameter, and returns one list
def getDaysBefore(num):
  today = datetime.date.today()
  oneday = datetime.timedelta(days=1)
  li = []
  for i in range(0, num):
    # Minus one day today, minus one day at a time 
    today = today - oneday
    # Converts a date to a string 
    li.append(datetostr(today))
  return li


# Converts a string to datetime type 
def strtodatetime(datestr, format):
  return datetime.datetime.strptime(datestr, format)


# The time is converted to a string , Format for 2015-02-02
def datetostr(date):
  return str(date)[0:10]


# The time is converted to a string , Format for 2015-02-02
def datetostr_secod(date):
  return str(date)[0:19]


# How many days are there between the two dates? 2015-2-04 and 2015-3-1
def datediff(beginDate, endDate):
  format = "%Y-%m-%d"
  bd = strtodatetime(beginDate, format)
  ed = strtodatetime(endDate, format)
  oneday = datetime.timedelta(days=1)
  count = 0
  while bd != ed:
    ed = ed - oneday
    count += 1
  return count


# The number of seconds between the two dates 
def datediff_seconds(beginDate, endDate):
  format = "%Y-%m-%d %H:%M:%S"
  if " " not in beginDate or ':' not in beginDate:
    bformat = "%Y-%m-%d"
  else:
    bformat = format
  if " " not in endDate or ':' not in endDate:
    eformat = "%Y-%m-%d"
  else:
    eformat = format
  starttime = strtodatetime(beginDate, bformat)
  endtime = strtodatetime(endDate, eformat)
  ret = endtime - starttime
  return ret.days * 86400 + ret.seconds


# Gets all The Times of the two time periods , return list
def getDays(beginDate, endDate):
  format = "%Y-%m-%d"
  begin = strtodatetime(beginDate, format)
  oneday = datetime.timedelta(days=1)
  num = datediff(beginDate, endDate) + 1
  li = []
  for i in range(0, num):
    li.append(datetostr(begin))
    begin = begin + oneday
  return li


# Get the current year   It's a string 
def getYear(date=datetime.date.today()):
  return str(date)[0:4]


# Get the current month   It's a string 
def getMonth(date=datetime.date.today()):
  return str(date)[5:7]


# Get current day   It's a string 
def getDay(date=datetime.date.today()):
  return str(date)[8:10]


# Get the current hour   It's a string 
def getHour(date=datetime.datetime.now()):
  return str(date)[11:13]


# Get the current minute   It's a string 
def getMinute(date=datetime.datetime.now()):
  return str(date)[14:16]


# Get current second   It's a string 
def getSecond(date=datetime.datetime.now()):
  return str(date)[17:19]


def getNow():
  return datetime.datetime.now()


print dateadd_day(10)
#2015-02-14 16:41:13.275000

print getYesterday()
#2015-02-03

print getToday()
#2015-02-04

print getDaysBefore(3)
#['2015-02-03', '2015-02-02', '2015-02-01']

print datediff('2015-2-01', '2015-10-05')
#246

print datediff_seconds('2015-02-04', '2015-02-05')
#86400

print datediff_seconds('2015-02-04 22:00:00', '2015-02-05')
#7200

print getDays('2015-2-03', '2015-2-05')
#['2015-02-03', '2015-02-04', '2015-02-05']

print datetostr_secod(getNow())
#2015-02-04 16:46:47

print str(getYear(dateadd_day(-50))) + '-'
  + getMonth() + '-'
  + getDay() + ' '
  + getHour() + ':'
  + getMinute() + ':'
  + getSecond()
#2014-02-04 16:59:04

print getNow()
#2015-02-04 16:46:47.454000


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