Python implementations are based on HTTP file transfer instances

This article illustrates an example of how Python implements HTTP file transfer. Share with you for your reference. The specific implementation method is as follows:

I. problems:

Because you need to take a recent look at the contents of the transfer file by POST request and write your own Server and Client to implement a simple HTTP file transfer tool

Ii. Implementation code

Server side:

#coding=utf-8

from BaseHTTPServer import BaseHTTPRequestHandler

import cgi

class   PostHandler(BaseHTTPRequestHandler):

    def do_POST(self):

        form = cgi.FieldStorage(

            fp=self.rfile,

            headers=self.headers,

            environ={'REQUEST_METHOD':'POST',

                     'CONTENT_TYPE':self.headers['Content-Type'],

                     }

        )

        self.send_response(200)

        self.end_headers()

        self.wfile.write('Client: %sn ' % str(self.client_address) )

        self.wfile.write('User-agent: %sn' % str(self.headers['user-agent']))

        self.wfile.write('Path: %sn'%self.path)

        self.wfile.write('Form data:n')

        for field in form.keys():

            field_item = form[field]

            filename = field_item.filename

            filevalue  = field_item.value

            filesize = len(filevalue)# The file size ( byte )

            print len(filevalue)

            with open(filename.decode('utf-8')+'a','wb') as f:

                f.write(filevalue)

        return

if __name__=='__main__':

    from BaseHTTPServer import HTTPServer

    sever = HTTPServer(('localhost',8080),PostHandler)

    print 'Starting server, use <Ctrl-C> to stop'

    sever.serve_forever()

#coding=utf-8

import requests

url = 'http://localhost:8080'

path = u'D: Fast dish ali head .jpg'

print path

files = {'file': open(path, 'rb')}

r = requests.post(url, files=files)

print r.url,r.text

I hope this article has helped you with your Python programming.