Simple implementation of Python single linked list
- 2020-04-02 14:07:47
- OfStack
This article illustrates the simple implementation of Python single linked list, and shares it with you for your reference. Specific methods are as follows:
In general, to define a single linked list, first define the linked list Element :Element. It contains three fields:
List: identifies which list you belong to
Datum: change the value of an element
Next: the location of the next node
The specific implementation code is as follows:
class LinkedList(object):
class Element(object):
def __init__(self,list,datum,next):
self._list = list
self._datum = datum
self._next = next
def getDatum(self):
return self._datum
datum = property(
fget = lambda self: self.getDatum())
def getNext(self):
return self._next
next = property(
fget = lambda self: self.getNext())
def __init__(self):
self._head = None
self._tail = None
def getHead(self):
return self._head
head = property(
fget = lambda self: self.getHead())
def prepend(self,item):
tmp = self.Element (self,item,self._head)
if self._head is None:
self._tail = tmp
self._head = tmp
def insert(self, pos, item):
i = 0
p = self._head
while p != None and i < pos -1:
p = p._next
i += 1
if p == None or i > pos-1:
return -1
tmp = self.Element(self, item, p._next)
p._next = tmp
return 1
def getItem(self, pos):
i = 0
p = self._head
while p != None and i < pos -1:
p = p._next
i += 1
if p == None or i > post-1:
return -1
return p._datum
def delete(self, pos):
i = 0
p = self._head
while p != None and i < pos -1:
p = p._next
i += 1
if p == None or i > post-1:
return -1
q = p._next
p._nex = q._next
datum = p._datum
return datum
def setItem(self, pos, item):
i = 0
p = self._head
while p != None and i < pos -1:
p = p._next
i += 1
if p == None or i > post-1:
return -1
p._datum = item
return 1
def find(self, pos, item):
i = 0
p = self._head
while p != None and i < pos -1:
if p._datum == item:
return 1
p = p._next
i += 1
return -1
def empty(self):
if self._head == None:
return 1
return 0
def size(self):
i = 0
p = self._head
while p != None and i < pos -1:
p = p._next
i += 1
return i
def clear(self):
self._head = None
self._tail = None
test = LinkedList()
test.prepend('test0')
print test.insert(1, 'test')
print test.head.datum
print test.head.next.datum
I hope this article has helped you with your Python programming.