Python implements batch replacement of file names and content replacement
- 2020-04-02 13:31:51
- OfStack
Specifies a folder, specifies a file type, and replaces the contents of all files under that folder.
Note that you need to specify coding for reading and writing under the window. You also need to specify #coding:utf-8 coding in the header of the file to avoid coding problems.
#coding:utf-8
import os
import os.path
path='.'
oldStr='.php'
newStr='.html'
for (dirpath, dirnames, filenames) in os.walk(path):
for file in filenames:
if os.path.splitext(file)[1]=='.html':
print(file)
filepath=os.path.join(dirpath,file)
try:
text_file = open(filepath, "r")
lines = text_file.readlines()
text_file.close()
output = open(filepath,'w',encoding= 'utf-8')
for line in lines:
#print(line)
if not line:
break
if(oldStr in line):
tmp = line.split(oldStr)
temp = tmp[0] + newStr + tmp[1]
output.write(temp)
else:
output.write(line)
output.close()
except Exception:
print(Exception)
break
This example allows you to replace file names and contents in batches
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import os, re
def multi_replace(text, adict):
rx = re.compile('|'.join(map(re.escape, adict)))
def xlat(match):
return adict[match.group(0)]
return rx.sub(xlat, text)
def batrename(curdir, pairs):
for fn in os.listdir(curdir):
newfn = multi_replace(fn, pairs)
if newfn != fn:
print("Renames %s to %s in %s." % (fn, newfn, curdir))
os.rename(os.path.join(curdir, fn), os.path.join(curdir, newfn))
file = os.path.join(curdir, newfn)
if os.path.isdir(file):
batrename(file, pairs)
continue
text = open(file).read()
newtext = multi_replace(text, pairs)
if newtext != text:
print("Renames %s." % (file,))
open(file, 'w').write(newtext)
if __name__=="__main__":
while True:
oldname = raw_input("Old name: ")
newname = raw_input("New name: ")
if oldname and newname:
batrename(os.path.abspath('.'), {oldname:newname})
else: break