Python calculates minimum priority queue code sharing

  • 2020-04-02 13:17:47
  • OfStack


# -*- coding: utf-8 -*-
class Heap(object):
    @classmethod
    def parent(cls, i):
        """ Parent subscript """
        return int((i - 1) >> 1);
    @classmethod
    def left(cls, i):
        """ Left son subscript """
        return (i << 1) + 1;
    @classmethod
    def right(cls, i):
        """ Right son subscript """
        return (i << 1) + 2;
class MinPriorityQueue(list, Heap):
    @classmethod
    def min_heapify(cls, A, i, heap_size):
        """ The minimum heap, A[i] Is the subtree of the root """
        l, r = cls.left(i), cls.right(i)
        if l < heap_size and A[l] < A[i]:
            least = l
        else:
            least = i
        if r < heap_size and A[r] < A[least]:
            least = r
        if least != i:
            A[i], A[least] = A[least], A[i]
            cls.min_heapify(A, least, heap_size)
    def minimum(self):
        """ Returns the smallest element, the pseudo-code is as follows: 
        HEAP-MINIMUM(A)
        1  return A[1]
        T(n) = O(1)
        """
        return self[0]
    def extract_min(self):
        """ Remove and return the smallest element. The pseudo-code is as follows: 
        HEAP-EXTRACT-MIN(A)
        1  if heap-size[A] < 1
        2    then error "heap underflow"
        3  min  please  A[1]
        4  A[1]  please  A[heap-size[A]] //The tail element comes first
        5  heap-size[A]  please  heap-size[A] - 1 //Reduce heap - size [A]
        6  MIN-HEAPIFY(A, 1) //Keep the minimum heap property
        7  return min
        T(n) =  Theta. (lgn)
        """
        heap_size = len(self)
        assert heap_size > 0, "heap underflow"
        val = self[0]
        tail = heap_size - 1
        self[0] = self[tail]
        self.min_heapify(self, 0, tail)
        self.pop(tail)
        return val
    def decrease_key(self, i, key):
        """ will i The value at PI goes down to PI key , the pseudo-code is as follows: 
        HEAP-DECREASE-KEY(A, i, key)
        1  if key > A[i]
        2    then error "new key is larger than current key"
        3  A[i]  please  key
        4  while i > 1 and A[PARENT(i)] > A[i] //Not the root and the parent is larger
        5    do exchange A[i] ↔ A[PARENT(i)] //Swap two elements
        6       i  please  PARENT(i) //Point to the parent location
        T(n) =  Theta. (lgn)
        """
        val = self[i]
        assert key <= val, "new key is larger than current key"
        self[i] = key
        parent = self.parent
        while i > 0 and self[parent(i)] > self[i]:
            self[i], self[parent(i)] = self[parent(i)], self[i]
            i = parent(i)
    def insert(self, key):
        """ will key insert A , the pseudo-code is as follows: 
        MIN-HEAP-INSERT(A, key)
        1  heap-size[A]  please  heap-size[A] + 1 //Increase the number of elements
        2  A[heap-size[A]]  please  + up  //We started off with a plus infinity
        3  HEAP-DECREASE-KEY(A, heap-size[A], key) //Reduce the new element to key
        T(n) =  Theta. (lgn)
        """
        self.append(float('inf'))
        self.decrease_key(len(self) - 1, key)
if __name__ == '__main__':
    import random
    keys = range(10)
    random.shuffle(keys)
    print(keys)
    queue = MinPriorityQueue() #  The insertion mode builds the minimum heap 
    for i in keys:
        queue.insert(i)
    print(queue)
    print('*' * 30)
    for i in range(len(queue)):
        val = i % 3
        if val == 0:
            val = queue.extract_min() #  Remove and return the smallest element 
        elif val == 1:
            val = queue.minimum() #  Return the smallest element 
        else:
            val = queue[1] - 10
            queue.decrease_key(1, val) # queue[1] To reduce 10
        print(queue, val)
    print([queue.extract_min() for i in range(len(queue))])


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