Python converts Arabic numerals into Chinese implementation code

  • 2020-04-02 09:43:44
  • OfStack

 
#!/usr/bin/python 
#-*- encoding: utf-8 -*- 
import types 
class NotIntegerError(Exception): 
pass 
class OutOfRangeError(Exception): 
pass 
_MAPPING = (u' zero ', u' one ', u' two ', u' three ', u' four ', u' five ', u' six ', u' seven ', u' eight ', u' nine ', ) 
_P0 = (u'', u' ten ', u' best ', u' thousand ', ) 
_S4, _S8, _S16 = 10 ** 4 , 10 ** 8, 10 ** 16 
_MIN, _MAX = 0, 9999999999999999 
def _to_chinese4(num): 
''''' conversion [0, 10000) Between the Arabic numerals  
''' 
assert(0 <= num and num < _S4) 
if num < 10: 
return _MAPPING[num] 
else: 
lst = [ ] 
while num >= 10: 
lst.append(num % 10) 
num = num / 10 
lst.append(num) 
c = len(lst) #  digits  
result = u'' 
for idx, val in enumerate(lst): 
if val != 0: 
result += _P0[idx] + _MAPPING[val] 
if idx < c - 1 and lst[idx + 1] == 0: 
result += u' zero ' 
return result[::-1].replace(u' ten ', u' ten ') 
def _to_chinese8(num): 
assert(num < _S8) 
to4 = _to_chinese4 
if num < _S4: 
return to4(num) 
else: 
mod = _S4 
high, low = num / mod, num % mod 
if low == 0: 
return to4(high) + u' wan ' 
else: 
if low < _S4 / 10: 
return to4(high) + u' Ten thousand ' + to4(low) 
else: 
return to4(high) + u' wan ' + to4(low) 
def _to_chinese16(num): 
assert(num < _S16) 
to8 = _to_chinese8 
mod = _S8 
high, low = num / mod, num % mod 
if low == 0: 
return to8(high) + u' Hundred million ' 
else: 
if low < _S8 / 10: 
return to8(high) + u' One hundred million ' + to8(low) 
else: 
return to8(high) + u' Hundred million ' + to8(low) 
def to_chinese(num): 
if type(num) != types.IntType and type(num) != types.LongType: 
raise NotIntegerError(u'%s is not a integer.' % num) 
if num < _MIN or num > _MAX: 
raise OutOfRangeError(u'%d out of range[%d, %d)' % (num, _MIN, _MAX)) 
if num < _S4: 
return _to_chinese4(num) 
elif num < _S8: 
return _to_chinese8(num) 
else: 
return _to_chinese16(num) 
if __name__ == '__main__': 
print to_chinese(9000) 

Python code that converts the amount from lowercase to uppercase
Function converts lowercase amounts less than 10 trillion yuan to uppercase
code
 
  def IIf( b, s1, s2): 
  if b: 
    return s1 
  else: 
    return s2 
def num2chn(nin=None): 
    cs = 
(' zero ',' one ',' Ii. ',' 3 ',' boss ',' wu ',' lu ',' Retailer, ','  ',' nine ',' To cardiac ',' points ',' Angle ',' round ',' Pick up ',' hk ',' micky ', 
' wan ',' Pick up ',' hk ',' micky ',' Hundred million ',' Pick up ',' hk ',' micky ',' wan ') 
    st = ''; st1='' 
    s = '%0.2f' % (nin)     
    sln =len(s) 
    if sln >; 15: return None 
    fg = (nin<1) 
    for i in range(0, sln-3): 
        ns = ord(s[sln-i-4]) - ord('0') 
        st=IIf((ns==0)and(fg or (i==8)or(i==4)or(i==0)), '', cs[ns]) 
      + IIf((ns==0)and((i<>;8)and(i<>;4)and(i<>;0)or fg 
and(i==0)),'', cs[i+13]) 
      + st 
        fg = (ns==0) 
    fg = False 
    for i in [1,2]: 
        ns = ord(s[sln-i]) - ord('0') 
        st1 = IIf((ns==0)and((i==1)or(i==2)and(fg or (nin<1))), '', cs[ns]) 
       + IIf((ns>;0), cs[i+10], IIf((i==2) or fg, '', ' The whole ')) 
       + st1 
        fg = (ns==0) 
    st.replace(' One hundred million ',' wan ') 
    return IIf( nin==0, ' zero ', st + st1) 
if __name__ == '__main__': 
  num = 12340.1 
  print num 
  print num2chn(num) 

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