Node. js Express Framework POST Method Detailed Explanation

  • 2021-07-13 04:19:05
  • OfStack

POST method

The following example demonstrates submitting two parameters in a form through the POST method, and we can use the process_post router in the server. js file to process the input:

The code for the index. htm file is modified as follows:


<html>
<body>
<form action="http://127.0.0.1:8081/process_post" method="POST">
First Name: <input type="text" name="first_name"> <br>

Last Name: <input type="text" name="last_name">
<input type="submit" value="Submit">
</form>
</body>
</html>

The code for the server. js file is modified as follows:


var express = require('express');
var app = express();
var bodyParser = require('body-parser');

//  Create  application/x-www-form-urlencoded  Code parsing 
var urlencodedParser = bodyParser.urlencoded({ extended: false })

app.use(express.static('public'));

app.get('/index.htm', function (req, res) {
  res.sendFile( __dirname + "/" + "index.htm" );
})

app.post('/process_post', urlencodedParser, function (req, res) {

  //  Output  JSON  Format 
  response = {
    first_name:req.body.first_name,
    last_name:req.body.last_name
  };
  console.log(response);
  res.end(JSON.stringify(response));
})

var server = app.listen(8081, function () {

 var host = server.address().address
 var port = server.address().port

 console.log(" Application instance, the access address is  http://%s:%s", host, port)

})

Execute the above code:


$ node server.js

Application example, the access address is http://0.0. 0.0: 8081

Browser access http://127.0.0.1: 8081/index. htm


Related articles: