javascript for the date difference method

This article illustrates the javascript method for finding date differences. To share with you for your reference, as follows:

<script type="text/javascript">
function daytonow(year, month, date){
 // The idea is to convert the two dates into timestamps in milliseconds, divided by each 1 The number of milliseconds in days tells you how many days are apart 
 //JS In the month from 0 Here we go, so month Need to get 1
 month--;
 // Bygone days 
 var tdate = new Date(year, month, date).getTime();
 // today 
 var tnow = new Date().getTime();
 var longdate = Math.ceil((tnow - tdate) / (1000 * 60 * 60 * 24));
 return longdate;
}
alert(daytonow(2009, 4, 5));
</script>

The difference of days between two dates:

// The difference in days between two date strings ,  before - after , sDate1-sDate2
function DateDiff(sDate1, sDate2) { //sDate1 and sDate2 is "2002-12-18" format 
  var aDate, oDate1, oDate2, iDays;
  aDate = sDate1.split("-");
  oDate1 = new Date(aDate[0], aDate[1] - 1, aDate[2]);
  aDate = sDate2.split("-");
  oDate2 = new Date(aDate[0], aDate[1] - 1, aDate[2]);
  iDays = parseInt(Math.abs(oDate1 - oDate2) / 1000 / 60 / 60 / 24);
  if ((oDate1 - oDate2) < 0) {
    return -iDays;
  }
  return iDays;
}
// The difference in days between two date strings ,  before - after , sDate1-sDate2
function DateDiff2(sDate1, sDate2) { //sDate1 and sDate2 is "12/18/2011" format 
  var oDate1, oDate2, iDays;
  oDate1 = new Date(sDate1);
  oDate2 = new Date(sDate2);
  var iDays = parseInt(Math.abs(oDate1 - oDate2) / 1000 / 60 / 60 / 24);
  if ((oDate1 - oDate2) < 0){
    return -iDays;
  }
  return iDays;
}

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I hope this article is helpful to JavaScript program design.