Java method of sorting arrays
- 2020-04-01 03:44:26
- OfStack
This article illustrates how Java sorts arrays. Share with you for your reference. The details are as follows:
public class Test1 {
public static void showArray(int[] array) {
for (int n = 0; n < array.length; n++) {
System.out.print(array[n]);
System.out.print(" ");
}
System.out.println();
}
public static int[] bubbleSort(int[] before) {
int t;
for (int i = 0; i < before.length; i++) {
for (int j = 0; j < before.length - i - 1; j++) {
if (before[j] > before[j + 1]) {
t = before[j];
before[j] = before[j + 1];
before[j + 1] = t;
}
}
}
return before;
}
public static void main(String[] args) {
int[] a = { 12, 24, 25, 4, 9, 68, 45, 7 };
System.out.println(" Before ordering: ");
showArray(a);
int[] b = bubbleSort(a);
System.out.println(" After the order: ");
showArray(b);
}
}
Execution results:
Before sorting:
12, 24, 25, 4, 9, 68, 45, 7
In order:
4, 7, 9, 12, 24, 25, 45, 68
I hope this article has been helpful to your Java programming.