Spring quick start example tutorial
- 2020-04-01 03:38:26
- OfStack
This article illustrates the basic configuration and inversion of control of spring. Share with you for your reference. The details are as follows:
Here we use maven to build Java projects, and the same applies without maven.
1. Create maven project, the project name I created is springdemo.
2. Add dependency package. I added the package through maven, and the configuration of maven is as follows:
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context</artifactId>
<version>4.0.1.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-core</artifactId>
<version>4.0.1.RELEASE</version>
</dependency>
Of course, you can also add jar files directly.
3. Create a simple package structure
I created package structures like entity, dao, business, etc.
Write simple code
User, empty code, as follows:
package com.chzhao.model;
public class User {
}
Interface IUserDao
package com.chzhao.dao;
import com.chzhao.model.User;
public interface IUserDao {
public User findUserById();
}
Interface implementation
package com.chzhao.dao;
import com.chzhao.model.User;
public class UserDaoImpl implements IUserDao {
public User findUserById() {
System.out.println("dao");
return null;
}
}
call
package com.chzhao.springdemo;
import com.chzhao.dao.IUserDao;
import com.chzhao.model.User;
public class UserManager {
public IUserDao getDao() {
return dao;
}
public void setDao(IUserDao dao) {
this.dao = dao;
}
private IUserDao dao;
public User findUser() {
return dao.findUserById();
}
}
The main initialization
package com.chzhao.springdemo;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
public class App {
public static void main(String[] args) {
ApplicationContext act = new ClassPathXmlApplicationContext(
"applicationContext.xml");
UserManager um = (UserManager) act.getBean("userManager");
um.findUser();
}
}
The corresponding configuration file
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">
<bean id="UserDaoImpl" class="com.chzhao.dao.UserDaoImpl"/>
<bean name="userManager" class="com.chzhao.springdemo.UserManager">
<property name="dao" >
<ref bean="UserDaoImpl"/>
</property>
</bean>
</beans>
That's the normal way.
Here's how.
First, the configuration file needs to be changed, as shown below
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">
<bean class="org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor" />
<bean id="UserDaoImpl" class="com.chzhao.dao.UserDaoImpl"/>
<bean name="userManager" class="com.chzhao.springdemo.UserManager"> </bean>
</beans>
Interface implementation
package com.chzhao.dao;
import org.springframework.stereotype.Repository;
import com.chzhao.model.User;
@Repository
public class UserDaoImpl implements IUserDao {
public User findUserById() {
System.out.println("dao");
return null;
}
}
call
package com.chzhao.springdemo;
import org.springframework.beans.factory.annotation.Autowired;
import com.chzhao.dao.IUserDao;
import com.chzhao.model.User;
public class UserManager {
@Autowired
private IUserDao dao;
public User findUser() {
return dao.findUserById();
}
}
The two methods implement the same thing.
I hope this article has been helpful to your Java programming.