Detailed explanation of java digital to Chinese character tool class
- 2021-07-22 09:41:01
- OfStack
In this paper, we share the specific codes of java digital to Chinese character tool class for your reference. The specific contents are as follows
/**
* Created by 33303 on 2017/7/28.
*/
import java.math.BigDecimal;
/**
* Convert numbers into capitals of RMB in Chinese <br>
*
*/
public class NumberToCN {
/**
* Capitalized digits in Chinese
*/
private static final String[] CN_UPPER_NUMBER = { " Zero ", " One ", " 2 ", " 3 ", " Four ",
" Wu ", " Land ", " Qi ", " Eight ", " Nine " };
/**
* In Chinese, monetary units are capitalized, which is similar to placeholders
*/
private static final String[] CN_UPPER_MONETRAY_UNIT = { " Points ", " Angle ", " Yuan ",
" Pick up ", " Bai ", " Thousands ", " Ten thousand ", " Pick up ", " Bai ", " Thousands ", " Billion ", " Pick up ", " Bai ", " Thousands ", " Mega ", " Pick up ",
" Bai ", " Thousands " };
/**
* Special character: whole
*/
private static final String CN_FULL = " Whole ";
/**
* Special character: negative
*/
private static final String CN_NEGATIVE = " Negative ";
/**
* Accuracy of the amount, the default value is 2
*/
private static final int MONEY_PRECISION = 2;
/**
* Special character: Zero whole
*/
private static final String CN_ZEOR_FULL = " Zero element " + CN_FULL;
/**
* Convert the input amount into the capital of RMB in Chinese
*
* @param numberOfMoney
* Amount entered
* @return Corresponding Chinese capitalization
*/
public static String number2CNMontrayUnit(BigDecimal numberOfMoney) {
StringBuffer sb = new StringBuffer();
// -1, 0, or 1 as the value of this BigDecimal is negative, zero, or
// positive.
int signum = numberOfMoney.signum();
// The case of zero yuan whole
if (signum == 0) {
return CN_ZEOR_FULL;
}
// The amount will be used here 4 Shed 5 Into
long number = numberOfMoney.movePointRight(MONEY_PRECISION)
.setScale(0, 4).abs().longValue();
// Get two decimal places
long scale = number % 100;
int numUnit = 0;
int numIndex = 0;
boolean getZero = false;
// Judge the last two digits, 1 Shared 4 Medium situation: 00 = 0, 01 = 1, 10, 11
if (!(scale > 0)) {
numIndex = 2;
number = number / 100;
getZero = true;
}
if ((scale > 0) && (!(scale % 10 > 0))) {
numIndex = 1;
number = number / 10;
getZero = true;
}
int zeroSize = 0;
while (true) {
if (number <= 0) {
break;
}
// Every time you get to the end, 1 Number
numUnit = (int) (number % 10);
if (numUnit > 0) {
if ((numIndex == 9) && (zeroSize >= 3)) {
sb.insert(0, CN_UPPER_MONETRAY_UNIT[6]);
}
if ((numIndex == 13) && (zeroSize >= 3)) {
sb.insert(0, CN_UPPER_MONETRAY_UNIT[10]);
}
sb.insert(0, CN_UPPER_MONETRAY_UNIT[numIndex]);
sb.insert(0, CN_UPPER_NUMBER[numUnit]);
getZero = false;
zeroSize = 0;
} else {
++zeroSize;
if (!(getZero)) {
sb.insert(0, CN_UPPER_NUMBER[numUnit]);
}
if (numIndex == 2) {
if (number > 0) {
sb.insert(0, CN_UPPER_MONETRAY_UNIT[numIndex]);
}
} else if (((numIndex - 2) % 4 == 0) && (number % 1000 > 0)) {
sb.insert(0, CN_UPPER_MONETRAY_UNIT[numIndex]);
}
getZero = true;
}
// Jean number Remove the last every time 1 Number
number = number / 10;
++numIndex;
}
// If signum == -1 The number entered is negative, and a special character is appended to the front: negative
if (signum == -1) {
sb.insert(0, CN_NEGATIVE);
}
// The number entered is two decimal places after the decimal point "00" In the case of, a special character should be appended at the end: whole
if (!(scale > 0)) {
sb.append(CN_FULL);
}
return sb.toString();
}
public static void main(String[] args) {
double money = 2020004.01;
BigDecimal numberOfMoney = new BigDecimal(money);
String s = NumberToCN.number2CNMontrayUnit(numberOfMoney);
System.out.println(" The amount you entered is: " "+ money +" " #--# [" +s.toString()+"]");
}
}