Java prints out the digits based on the number of positive integers in reverse order
- 2020-06-15 08:26:47
- OfStack
Give me a positive integer with no more than 5 digits. Find out how many digits it is.
Program design:
import java.util.Scanner;
public class Ex24 {
public static void main(String[] args) {
Ex24 tn = new Ex24();
Scanner s = new Scanner(System.in);
long a = s.nextLong();
if(a < 0 || a > 100000) {
System.out.println("Error Input, please run this program Again");
System.exit(0);
}
if(a >=0 && a <=9) {
System.out.println( a + " is 1 digits ");
System.out.println(" The output in reverse order is " + '\n' + a);
} else if(a >= 10 && a <= 99) {
System.out.println(a + " is 2 digits ");
System.out.println(" The output in reverse order is " );
tn.converse(a);
} else if(a >= 100 && a <= 999) {
System.out.println(a + " is 3 digits ");
System.out.println(" The output in reverse order is " );
tn.converse(a);
} else if(a >= 1000 && a <= 9999) {
System.out.println(a + " is 4 digits ");
System.out.println(" The output in reverse order is " );
tn.converse(a);
} else if(a >= 10000 && a <= 99999) {
System.out.println(a + " is 5 digits ");
System.out.println(" The output in reverse order is " );
tn.converse(a);
}
}
public void converse(long l) {
String s = Long.toString(l);
char[] ch = s.toCharArray();
for(int i=ch.length-1; i>=0; i--) {
System.out.print(ch[i]);
}
}
}