java method to get the largest number from the int array
- 2020-06-12 09:04:24
- OfStack
The first thing is to have the concept of array, know what is an array, simply speaking is to store 1 group of data 1 combination, is an array... Ha ha
Given an int array, the program gets the maximum number from the array.
Thinking analysis:
1, 1 array can have a lot of Numbers, so if you want to take the largest number, that's just a number and a number and you can compare them and you can pick them, right
So: first define a variable to be the first number of the array, and then compare it with the second and third number of the array, when it encounters a larger number than itself, assign the dozen value to the variable, and then traverse to the end.
Code:
package com.itheima;
/**
* 2 , known 1 a int An array of , Program to get the largest number from an array .
* @author 281167413@qq.com
*/
public class Test2 {
public static void main(String[] args)
{
int values[] = {1,2,9,3,4,5};
int max = getMax(values);
System.out.printf("The MAX values: %d\n", max);
}
public static int getMax(int[] values)
{
int tmp=Integer.MIN_VALUE;
if(null!=values)
{
tmp=values[0];
for(int i=0; i<values.length; i++)
{
if(tmp<values[i])
{
tmp = values[i];
}
}
}
return tmp;
}
}
This is how java gets the largest number from the int array, as shown in 1.