PHP displays the image under the specified path

function getAllDirAndFile($path) 
{ 
if(is_file($path)) 
{ 
if(isImage($path)) 
{ 
$str=""; 
$str.='<table style="border:solid 1px blue;" width="95%">'; 
$str.="<tr>"; 
$path=iconv("gb2312","utf-8",$path); 
$str.="<td width=80%>".$path."</td><td width=15%><img src=".$path." style='width:50px;height:50px;'></td>"; 
$str.="</tr>"; 
$str.="</table>"; 
echo $str; 
} 
} 
else 
{ 
$resource=opendir($path); 
while ($file=readdir($resource)) 
{ 
if($file!="." && $file!="..") 
{ 
getAllDirAndFile($path."/".$file); 
} 
} 
} 
} 

function isImage($filePath) 
{ 
$fileTypeArray=array("jpg","png","bmp","jpeg","gif","ico"); 
$filePath=strtolower($filePath); 
$lastPosition=strrpos($filePath,"."); 
$isImage=false; 
if($lastPosition>=0) 
{ 
$fileType=substr($filePath,$lastPosition+1,strlen($filePath)-$lastPosition); 
if(in_array($fileType,$fileTypeArray)) 
{ 
$isImage=true; 
} 
} 
return $isImage; 
}