PHP Processing JSON String key Lack of Double Quotation Marks

This article describes the example of PHP processing JSON string key lack of quotation marks solution, to share for your reference. The specific methods are as follows:

Typically, JSON strings are strings in the form of key: value, and normal key is enclosed in double quotation marks.

For example:

<?php
$data = array('name'=>'fdipzone');
echo json_encode($data);            // {"name":"fdipzone"}
print_r(json_decode(json_encode($data), true)); //Array ( [name] => fdipzone )
?>

However, json_decode fails if the key of the json string is missing a double reference.

<?php
$str = '{"name":"fdipzone"}';
var_dump(json_decode($str, true)); // array(1) { ["name"]=> string(8) "fdipzone" }

$str1 = '{name:"fdipzone"}';
var_dump(json_decode($str1, true)); // NULL
?>

Solution: Judge whether there is a lack of key with double citations. If there is a lack, replace it with "key" with regularity first, and then perform json_decode operation.

<?php
/**  Compatible key There is no double citation JSON String parsing 
* @param String $str JSON String 
* @param boolean $mod true:Array,false:Object
* @return Array/Object
*/
function ext_json_decode($str, $mode=false){
  if(preg_match('/\w:/', $str)){
    $str = preg_replace('/(\w+):/is', '"$1":', $str);
  }
  return json_decode($str, $mode);
}

$str = '{"name":"fdipzone"}';
var_dump(ext_json_decode($str, true)); // array(1) { ["name"]=> string(8) "fdipzone" }

$str1 = '{name:"fdipzone"}';
var_dump(ext_json_decode($str1, true)); // array(1) { ["name"]=> string(8) "fdipzone" }
?>

I hope this article is helpful to everyone's study of PHP programming.