php XMLHttpRequest of Ajax cannot set a custom Referer solution

  • 2020-05-10 17:49:27
  • OfStack

Solution: use a server as a proxy.
In PHP, use my favorite and most powerful CURL, heh heh
The following is an example code to query a domain name on the Internet
 
<?php 
$dn = $_GET['dn']; //  The domain name ,  Do not include www 
$ex = $_GET['ex']; //  Top-level domain names ,  Such as  .com, .cn,  Including the first one . 
//  Check to see if the domain name has been registered  
$url = 'http://pandavip.www.net.cn/check/check_ac1.cgi'; 
$ch = curl_init($url); 
curl_setopt($ch, CURLOPT_POST, true); // POST 
curl_setopt($ch, CURLOPT_POSTFIELDS, 'domain='.$dn.$ex); 
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:8.0) Gecko/20100101 Firefox/8.0'); 
curl_setopt($ch, CURLOPT_COOKIE, '__utma=1.1486902564.1322109246.1322109246.1322109246.1; __utmz=1.1322109246.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none); AdSource=GOOGLE%u641C%u7D22; AdWordID=gg96011009070005; __utmc=1'); 
curl_setopt($ch, CURLOPT_HTTPHEADER, array( 
'X-Requested-With' => 'XMLHttpRequest', //  Set to Ajax way  
'Referer' => 'http://pandavip.www.net.cn/cgi-bin/Check.cgi?queryType=0&domain1='.$dn.'&image.x=0&image.y=0&domain='.$dn.'&big5=n&sign=2&url=www.net.cn&'.trim($ex, '.').'=yes' //  An impostor ,  Hey hey  
)); 
curl_exec($ch); //  Returns the query results to the front end ,  with JS To deal with  

Related articles: