The Java implementation recursively computes the number of 1's in the binary representation
- 2020-04-01 03:51:35
- OfStack
With the help of Java language, recursive algorithm is used to calculate the number of 1 in the binary representation of integer N
/*use the recursive algorithme to calculate
* the number of "1" in the binary expression
* of an Integer N.
* Note:if N is an odd, then
* the result is the result of N/2 plus 1.
* And the program use the bit operation to
* improve efficency ,though it's seemingly
* not necessary ,but the idea I think is good.
* The program is writed by Zewang Zhang ,at
* 2015-5-4,in SYSU dorms.
*/
public class CalculateNumberInBinaryExpression {
//Main method.
public static void main(String[] args) {
//For example ,make N equals 13 ,the result shows 3
System.out.println(numOfEven(13));
//For example ,make N equals 128 ,the result shows 1
System.out.println(numOfEven(128));
}
//The static method of numOfEven is the recursive method.
public static int numOfEven(int x) {
//The base of recursive.
if(x==0) {
return 0;
}
//If x is an odd.
else if(x%2!=0) {
return numOfEven(x>>1)+1;
}
//If x is an even except 0.
else {
while(x%2==0) {
x=(x>>1);
}
return numOfEven(x);
}
}
}
The simplest, but untested :)
public int a(int i){
if(i==0||i==1) return i;
return i%2+a(i/2);
}
The above is all the content of this article, I hope you can enjoy it.