Java method of sorting arrays

This article illustrates how Java sorts arrays. Share with you for your reference. The details are as follows:

public class Test1 { 
  public static void showArray(int[] array) { 
    for (int n = 0; n < array.length; n++) { 
      System.out.print(array[n]); 
      System.out.print(" "); 
    } 
    System.out.println(); 
  } 
  public static int[] bubbleSort(int[] before) { 
    int t; 
    for (int i = 0; i < before.length; i++) { 
      for (int j = 0; j < before.length - i - 1; j++) { 
        if (before[j] > before[j + 1]) { 
          t = before[j]; 
          before[j] = before[j + 1]; 
          before[j + 1] = t; 
        } 
      } 
    } 
    return before; 
  } 
  public static void main(String[] args) { 
    int[] a = { 12, 24, 25, 4, 9, 68, 45, 7 }; 
    System.out.println(" Before ordering: "); 
    showArray(a); 
    int[] b = bubbleSort(a); 
    System.out.println(" After the order: "); 
    showArray(b); 
  } 
}

Execution results:

Before sorting:  
12, 24, 25, 4, 9, 68, 45, 7   
In order:  
4, 7, 9, 12, 24, 25, 45, 68

I hope this article has been helpful to your Java programming.