JAVA method of randomly shuffling array order

  • 2020-04-01 03:33:43
  • OfStack

This article illustrates a JAVA method for randomly shuffling arrays. Share with you for your reference. The specific implementation method is as follows:

import java.util.Random;    
   
public class RandomSort {   
    private Random random = new Random();   
    //Array size & NBSP;     < br / >     private static final int SIZE = 10;   
    //Array & PI to be reordered;     < br / >     private int[] positions = new int[SIZE];   
       
    public RandomSort() {   
        for(int index=0; index<SIZE; index++) {   
            //Initializes the array with the index as the element value & NBSP;     < br / >             positions[index] = index;   
        }   
        //Print out the value of the array sequentially & NBSP;     < br / >         printPositions(); 
    }   
       
    //Reorder       < br / >     public void changePosition() {   
        for(int index=SIZE-1; index>=0; index--) {   
            //You take a random value from 0 to index, and you swap & PI with the element at index;     < br / >             exchange(random.nextInt(index+1), index);   
        }   
        printPositions();   
    }   
       
    //Swap places & NBSP;     < br / >     private void exchange(int p1, int p2) {   
        int temp = positions[p1];   
        positions[p1] = positions[p2];   
        positions[p2] = temp;  //A better place & NBSP; < br / >     }   
       
    //Print the value of the array & NBSP;     < br / >     private void printPositions() {   
        for(int index=0; index<SIZE; index++) {   
            System.out.print(positions[index]+" ");            
        }   
        System.out.println();   
    }   
   
    public static void main(String[] args) {   
        RandomSort rs = new RandomSort();   
        rs.changePosition();   
        rs.changePosition();   
        rs.changePosition();   
    }   
}

I hope this article has been helpful to your Java programming.


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