Java implements the method of Fibonacci sequence based on high precision integer

  • 2020-04-01 03:29:33
  • OfStack

This article is an example of how to implement Fibonacci sequence in Java based on high precision integer. Specific methods are as follows:


package com.java.learning.recursion;
import java.math.*;
public class MainClass {
  public static void main(String args[]){
    for(int i = 0; i < 100; i++){
      f(i+1);
    }
  }
   
  public static BigInteger f(long n){
    if(n <= 2){
      return new BigInteger("1");
    }else{
      BigInteger n1 = new BigInteger("1");
      BigInteger n2 = new BigInteger("1");
      BigInteger temp = new BigInteger("0");
       
      for(long i = 0; i < n -2; i++){
        temp = n1.add(n2);
        n1 = n2;
        n2 = temp;
      }
      System.out.println(" The first " + n + " Items as follows: " + n2);
      return n2;
    }
  }
}

I hope this article has been helpful to your Java programming.


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