A method to generate 8 random Numbers that do not repeat

  • 2020-04-01 02:21:13
  • OfStack

 
package com.jjinfo.common.util; 
import java.util.Arrays; 
import java.util.Random; 

 
public class RandomNumberGenerator { 

 
public static String generateNumber() { 
String no=""; 
//Initializes the alternate array
int[] defaultNums = new int[10]; 
for (int i = 0; i < defaultNums.length; i++) { 
defaultNums[i] = i; 
} 

Random random = new Random(); 
int[] nums = new int[LENGTH]; 
//The partial length that can be selected from the default array
int canBeUsed = 10; 
//Populate the target array
for (int i = 0; i < nums.length; i++) { 
//Stores randomly selected Numbers in the target array
int index = random.nextInt(canBeUsed); 
nums[i] = defaultNums[index]; 
//Drop the used Numbers at the end of the alternate array and reduce the optional area
swap(index, canBeUsed - 1, defaultNums); 
canBeUsed--; 
} 
if (nums.length>0) { 
for (int i = 0; i < nums.length; i++) { 
no+=nums[i]; 
} 
} 

return no; 
} 
private static final int LENGTH = 8; 

private static void swap(int i, int j, int[] nums) { 
int temp = nums[i]; 
nums[i] = nums[j]; 
nums[j] = temp; 
} 

public static String generateNumber2() { 
String no=""; 
int num[]=new int[8]; 
int c=0; 
for (int i = 0; i < 8; i++) { 
num[i] = new Random().nextInt(10); 
c = num[i]; 
for (int j = 0; j < i; j++) { 
if (num[j] == c) { 
i--; 
break; 
} 
} 
} 
if (num.length>0) { 
for (int i = 0; i < num.length; i++) { 
no+=num[i]; 
} 
} 
return no; 
} 

public static void main(String[] args) { 
for (int i = 0; i < 10; i++) { 
// System.out.println(generateNumber()); 
System.out.println(generateNumber2()); 
} 
} 
} 

Related articles: