In Java the IP address is obtained by the network card name

  • 2020-04-01 01:39:51
  • OfStack


package me.xuzs.sso.test;
import java.net.InetAddress;
import java.net.NetworkInterface;
import java.net.SocketException;
import java.util.Enumeration;
public class InternetTest {
    public static void main(String[] args) {
        String netCard = "lo";
        try {
            Enumeration<NetworkInterface> netInterfaces = NetworkInterface
                    .getNetworkInterfaces();
            if (netInterfaces.hasMoreElements()) {
                NetworkInterface netInterface = netInterfaces.nextElement();
                if (netCard.equals(netInterface.getName())) {
                    //Child interface, Linux will take the parent interface??
                    Enumeration<NetworkInterface> subnetInterfaces = netInterface
                            .getSubInterfaces();
                    while (subnetInterfaces.hasMoreElements()) {
                        NetworkInterface subnetInterface = subnetInterfaces
                                .nextElement();
                        System.out.println(subnetInterface.getName());
                        Enumeration<InetAddress> subaddresses = netInterface
                                .getInetAddresses();
                        while (subaddresses.hasMoreElements()) {
                            InetAddress subaddress = subaddresses.nextElement();
                            System.out.println(subaddress.getHostAddress());
                        }
                    }
                    //Print all IP under the interface
                    System.out.println(netInterface.getName());
                    Enumeration<InetAddress> addresses = netInterface
                            .getInetAddresses();
                    while (addresses.hasMoreElements()) {
                        InetAddress address = addresses.nextElement();
                        System.out.println(address.getHostAddress());
                    }
                }
            }
        } catch (SocketException e) {
            e.printStackTrace();
        }
    }
}


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