java method to get the largest number from the int array

The first thing is to have the concept of array, know what is an array, simply speaking is to store 1 group of data 1 combination, is an array... Ha ha

Given an int array, the program gets the maximum number from the array.

Thinking analysis:

1, 1 array can have a lot of Numbers, so if you want to take the largest number, that's just a number and a number and you can compare them and you can pick them, right
So: first define a variable to be the first number of the array, and then compare it with the second and third number of the array, when it encounters a larger number than itself, assign the dozen value to the variable, and then traverse to the end.

Code:

package com.itheima;
/**
 * 2 ,   known 1 a int An array of ,  Program to get the largest number from an array .
 * @author 281167413@qq.com
 */
public class Test2 {
	public static void main(String[] args)
	{
		int values[] = {1,2,9,3,4,5};
		
		int max = getMax(values);
		
		System.out.printf("The MAX values: %d\n", max);
	}
	public static int getMax(int[] values)
	{
		int tmp=Integer.MIN_VALUE;
		
		if(null!=values)
		{
			tmp=values[0];
			for(int i=0; i<values.length; i++)
			{
				if(tmp<values[i])
				{
					tmp = values[i];
				}
			}
		}
		
		return tmp;		
	}
}

This is how java gets the largest number from the int array, as shown in 1.