GO language to achieve file upload code sharing
- 2020-05-30 20:19:38
- OfStack
The functionality is simple, the code is simple, and there's no more crap here.
package main
import (
"fmt"
"io"
"net/http"
"os"
)
const (
upload_path string = "./upload/"
)
func helloHandle(w http.ResponseWriter, r *http.Request) {
io.WriteString(w, "hello world!")
}
// upload
func uploadHandle(w http.ResponseWriter, r *http.Request) {
// Determine the method from the request
if r.Method == "GET" {
io.WriteString(w, "<html><head><title> My first 1 A page </title></head><body><form action='' method=\"post\" enctype=\"multipart/form-data\"><label> To upload pictures </label><input type=\"file\" name='file' /><br/><label><input type=\"submit\" value=\" To upload pictures \"/></label></form></body></html>")
} else {
// Get file content To get it like this
file, head, err := r.FormFile("file")
if err != nil {
fmt.Println(err)
return
}
defer file.Close()
// Create a file
fW, err := os.Create(upload_path + head.Filename)
if err != nil {
fmt.Println(" File creation failed ")
return
}
defer fW.Close()
_, err = io.Copy(fW, file)
if err != nil {
fmt.Println(" File save failed ")
return
}
//io.WriteString(w, head.Filename+" Save success ")
http.Redirect(w, r, "/hello", http.StatusFound)
//io.WriteString(w, head.Filename)
}
}
func main() {
// Start the 1 a http The server
http.HandleFunc("/hello", helloHandle)
// upload
http.HandleFunc("/image", uploadHandle)
err := http.ListenAndServe(":8080", nil)
if err != nil {
fmt.Println(" Server startup failed ")
return
}
fmt.Println(" Server started successfully ")
}
The above is the content of this article, hope you can enjoy it, can help you learn go language.