C Acquisition of Pinyin Initials of Chinese Characters
- 2021-07-06 11:36:22
- OfStack
Acquiring the first letter of Chinese Pinyin is a function that is often needed in the process of doing projects. Today, we mainly discuss how to obtain the first letter of Chinese Pinyin under C #
/// <summary>
/// In the specified string list CnStr Retrieve a string that matches the Pinyin index in
/// </summary>
/// <param name="CnStr"> Chinese character string </param>
/// <returns> Corresponding Chinese Pinyin initials </returns>
public static string GetSpellCode(string CnStr) {
string strTemp="";
int iLen=CnStr.Length;
int i=0;
for (i=0;i<=iLen-1;i++) {
strTemp+=GetCharSpellCode(CnStr.Substring(i,1));
}
return strTemp;
}
/// <summary>
/// Get 1 Pinyin number of Chinese characters 1 Three letters, if it is 1 English letters return capital letters directly
/// </summary>
/// <param name="CnChar"> Single Chinese character </param>
/// <returns> Single capital letter </returns>
private static string GetCharSpellCode(string CnChar) {
long iCnChar;
byte[] ZW = System.Text.Encoding.Default.GetBytes(CnChar);
// If it is a letter, it returns directly
if (ZW.Length==1) {
return CnChar.ToUpper();
}
else {
// get the array of byte from the single char
int i1 = (short)(ZW[0]);
int i2 = (short)(ZW[1]);
iCnChar = i1*256+i2;
}
// iCnChar match the constant
if ((iCnChar>=45217) && (iCnChar<=45252)) {
return "A";
}
else if ((iCnChar>=45253) && (iCnChar<=45760)) {
return "B";
} else if ((iCnChar>=45761) && (iCnChar<=46317)) {
return "C";
} else if ((iCnChar>=46318) && (iCnChar<=46825)) {
return "D";
} else if ((iCnChar>=46826) && (iCnChar<=47009)) {
return "E";
} else if ((iCnChar>=47010) && (iCnChar<=47296)) {
return "F";
} else if ((iCnChar>=47297) && (iCnChar<=47613)) {
return "G";
} else if ((iCnChar>=47614) && (iCnChar<=48118)) {
return "H";
} else if ((iCnChar>=48119) && (iCnChar<=49061)) {
return "J";
} else if ((iCnChar>=49062) && (iCnChar<=49323)) {
return "K";
} else if ((iCnChar>=49324) && (iCnChar<=49895)) {
return "L";
} else if ((iCnChar>=49896) && (iCnChar<=50370)) {
return "M";
}else if ((iCnChar>=50371) && (iCnChar<=50613)) {
return "N";
} else if ((iCnChar>=50614) && (iCnChar<=50621)) {
return "O";
} else if ((iCnChar>=50622) && (iCnChar<=50905)) {
return "P";
} else if ((iCnChar>=50906) && (iCnChar<=51386)) {
return "Q";
} else if ((iCnChar>=51387) && (iCnChar<=51445)) {
return "R";
} else if ((iCnChar>=51446) && (iCnChar<=52217)) {
return "S";
} else if ((iCnChar>=52218) && (iCnChar<=52697)) {
return "T";
} else if ((iCnChar>=52698) && (iCnChar<=52979)) {
return "W";
} else if ((iCnChar>=52980) && (iCnChar<=53640)) {
return "X";
} else if ((iCnChar>=53689) && (iCnChar<=54480)) {
return "Y";
} else if ((iCnChar>=54481) && (iCnChar<=55289)) {
return "Z";
} else
return ("?");
}
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