C++ to achieve large number multiplication algorithm code
- 2020-04-02 03:01:57
- OfStack
C++ to achieve large number multiplication algorithm code
//Large number multiplication algorithm
#include<iostream>
#include<string>
#include<cstring>
using namespace std;
int main()
{
string num1,num2;
cin >> num1 >> num2;
//cout << num1.size() << " " << num2.size() << endl;
const char* n1;
const char* n2;
if (num1.size() < num2.size())
{
n1 = num2.c_str();
n2 = num1.c_str();
}
else
{
n1 = num1.c_str();
n2 = num2.c_str();
}
char* n = new char[strlen(n1)+strlen(n2)+1];
for (unsigned int i = 0; i < strlen(n1)+strlen(n2); i++)
n[i] = '0';
n[strlen(n1)+strlen(n2)]='0';
//cout << strlen(n) << endl;
int count = 0,flag = 0;
for (int i = strlen(n1)-1; i >= 0; i--)
{
flag++;
int x1 = n1[i]-'0';
//Cout <<"N1 ["<<I <<"] is: "<<The x1 <<Endl; < br / >
char carry = '0';
for (int j = strlen(n2)-1; j >= 0; j--)
{
int x2 = n2[j]-'0';
//Cout <<"N2 ["<<j <<"] is: "<<X2 <<Endl; < br / >
//Cout <<"The previous value of the current bit unchanged is:" <<N [count] <<Endl; < br / >
int sum = x1*x2 + (carry-'0') + n[count]-'0';
//cout << "sum is " << sum << endl;
n[count++] = (sum % 10)+'0';
carry = (sum / 10)+'0';
//Cout <<"The current bit value is:" <<N [count - 1] <<Endl; < br / >
//Cout <<The value of "carry is: "<<Carry <<Endl; < br / >
}
if (carry != '0')
{
n[count] = carry;
count = flag;
//Cout <<"The current bit value is:" <<N [count] <<Endl; < br / >
}
else
count = flag;
}
for (int i = strlen(n)-1; i >= 0; i--)
{
if ((i == strlen(n)-1)&&(n[i] == '0'))
continue;
cout << n[i];
}
cout << endl;
delete[]n;
system("pause");
return 0;
}
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