A balanced binary tree implementation example
- 2020-04-02 02:06:42
- OfStack
#include<cstdio>
#include<cstdlib>
#define LH 1
#define EH 0
#define RH -1
using namespace std;
typedef struct BTNode
{
int data;
int BF;//Balance factor
struct BTNode *lchild,*rchild;
}BTNode,*BTree;
void R_Rotate(BTree *p)//The binary sort tree with p as the root node is rotated to the right
{
BTree L;
L=(*p)->lchild;
(*p)->lchild=L->rchild;
L->rchild=(*p);
*p=L;//P points to the new root node
}
void L_Rotate(BTree *p)//The binary sort tree with p as root node is rotated to the left
{
BTree R;
R=(*p)->rchild;
(*p)->rchild=R->lchild;
R->lchild=(*p);
*p=R;
}
void LeftBalance(BTree *T)
{
BTree L,Lr;
L=(*T)->lchild;
switch(L->BF)
{
//Check the left subtree equilibrium degree of T and make the corresponding equilibrium treatment
case LH://The new node is inserted into the left subtree of the left child of T to do a single dextro
(*T)->BF=L->BF=EH;
R_Rotate(T);
break;
case RH://The new insertion node is in the right subtree of the left child of T, doing double rotation
Lr=L->rchild;
switch(Lr->BF)
{
case LH:
(*T)->BF=RH;
L->BF=EH;
break;
case EH:
(*T)->BF=L->BF=EH;
break;
case RH:
(*T)->BF=EH;
L->BF=LH;
break;
}
Lr->BF=EH;
L_Rotate(&(*T)->lchild);
R_Rotate(T);
}
}
void RightBalance(BTree *T)
{
BTree R,Rl;
R=(*T)->rchild;
switch(R->BF)
{
case RH://The new node is inserted into the right subtree of the right child of T, and it needs to be single handed
(*T)->BF=R->BF=EH;
L_Rotate(T);
break;
case LH://The new node is inserted into the left subtree of the right child of T, and it needs to be double-rotated
Rl=R->lchild;
switch(Rl->BF)
{
case LH:
(*T)->BF=EH;
R->BF=RH;
break;
case EH:
(*T)->BF=R->BF=EH;
break;
case RH:
(*T)->BF=LH;
R->BF=EH;
break;
}
Rl->BF=EH;
R_Rotate(&(*T)->rchild);
L_Rotate(T);
}
}
bool InsertAVL(BTree *T,int e,bool *taller)//The variable taller responds to whether T is taller or not
{
if(!*T)
{
*T=(BTree)malloc(sizeof(BTNode));
(*T)->data=e;
(*T)->lchild=(*T)->rchild=NULL;
(*T)->BF=EH;
*taller=true;
}
else
{
if(e==(*T)->data)//Do not insert
{
*taller=false;
return false;
}
if(e<(*T)->data)
{
if(!InsertAVL(&(*T)->lchild,e,taller))//Not insert
return false;
if(*taller)//To insert the left subtree, and the left subtree gets taller
{
switch((*T)->BF)
{
case LH://The original left subtree is higher than the right subtree, so we need to do left balance
LeftBalance(T);
*taller=false;
break;
case EH://Originally about subtree height, now because of the left subtree height and tree height
(*T)->BF=LH;
*taller=true;
break;
case RH://Originally the right subtree is higher than the left subtree, now the left subtree is equal in height
(*T)->BF=EH;
*taller=false;
break;
}
}
}
else
{
//Search in the right subtree of T
if(!InsertAVL(&(*T)->rchild,e,taller))
return false;
if(*taller)//Insert the right subtree, and the right subtree grows
{
switch((*T)->BF)
{
case LH://The left subtree was originally higher than the right subtree, but now the left subtree is equal in height
(*T)->BF=EH;
*taller=false;
break;
case EH://Now the right subtree is higher than the left subtree
(*T)->BF=RH;
*taller=true;
break;
case RH://The right subtree was taller than the left subtree, but now it needs to be balanced
RightBalance(T);
*taller=false;
break;
}
}
}
}
return true;
}
bool Find(BTree T,int key)
{
if(!T)
return false;
else if(T->data==key)
return true;
else if(T->data<key)
return Find(T->rchild,key);
else
return Find(T->lchild,key);
}
void Output(BTree T)
{
if(T)
{
printf("%d",T->data);
if(T->lchild||T->rchild)
{
printf("(");
Output(T->lchild);
printf(",");
Output(T->rchild);
printf(")");
}
}
}
int main(int argc,char *argv[])
{
int i;
int A[]={3,2,1,4,5,6,7,10,9,8};
BTree T=NULL;
bool taller;
for(i=0;i<sizeof(A)/sizeof(int);i++)
InsertAVL(&T,A[i],&taller);
Output(T);
printf("n");
if(Find(T,6))
printf("6 is find in the AVL tree!n");
else
printf("6 is not find in the AVL tree!n");
return 0;
}