How to call the function of implementation code by function pointer
- 2020-04-02 01:24:57
- OfStack
Description:
A pointer can not only point to an integer, floating point, character, string variable, but also to an array, and can also point to a function.
A function is assigned an entry address at compile time. The function entry address is called the function pointer. You can point to a function with a pointer variable and then call the function from that pointer variable.
The method to define the pointer variable to the function is:
int (*p) (int ,int );
Int [function type pointed to by pointer variable p] (*p) [p is pointer variable pointed to by function] (int,int) [parameter type pointed to by p];
Compare with the prototype of the function
int max (int, int );
Int [function type] Max [function name] (int,int) [function parameter type];
An example:
General method code:
#include<iostream>
using namespace std;
int main(){
int max(int x,int y);
int a,b,c,m;
cout<<"Please input three integers:"<<endl;
cin>>a>>b>>c;
m=max(max(a,b),c);
cout<<"Max="<<m<<endl;
return 0;
}
int max(int x,int y){
int z;
if(x>y){
z=x;
} else{
z=y;
}
return z;
}
We then define a pointer variable that points to the Max function and then call the function from that pointer variable.
Call the function by (*p)
#include<iostream>
using namespace std;
int main(){
int max(int x,int y);
int (*p) (int x,int y);
p=max;
int a,b,c,m;
cout<<"Please input three integers:"<<endl;
cin>>a>>b>>c;
m=(*p)((*p)(a,b),c);
cout<<"Max="<<m<<endl;
return 0;
}
int max(int x,int y){
int z;
if(x>y){
z=x;
} else{
z=y;
}
return z;
}
Functions can be called directly through pointer p
#include<iostream>
using namespace std;
int main(){
int max(int x,int y);
int (*p) (int x,int y);
p=max;
int a,b,c,m;
cout<<"Please input three integers:"<<endl;
cin>>a>>b>>c;
m=p(p(a,b),c);
cout<<"Max="<<m<<endl;
return 0;
}
int max(int x,int y){
int z;
if(x>y){
z=x;
} else{
z=y;
}
return z;
}
Takes a pointer to a function as an argument
One of the most common USES of a function pointer variable is as an argument to a function, passing the function name to the parameter of another function. So that you can call different functions in the process of calling a function, given different arguments.
For example, using this method, the two functions y1= (x+1) ^1; Y2 = (2 x + 3) ^ 2 ; Y3 = (x ^ 2 + 1) ^ 3
Analysis: I'm going to write three functions f1,f2, and f3 to evaluate the three functions x plus 1,2,x plus 3,x squared plus 1.
Then write a generic function called Squar, which has two parameters: the a power and the pointing function,
Program code:
#include<iostream>
#include<math.h>
using namespace std;
double fun1(double n){
double r;
r=n+1;
return r;
}
double fun2(double n){
double r;
r=2*n+3;
return r;
}
double fun3(double n){
double r;
r=(pow(n,2)+1);
return r;
}
double Squar(int a, double x, double(*p)(double )){
double r,z;
z=(*p)(x);
r=pow(z,a);
return r;
}
int main(){
double fun1(double n);
double fun2(double n);
double fun3(double n);
double Squar(int a, double x, double(*p)(double ));
double x;
cout<<"Please input x:";
cin>>x;
cout<<"(x+1)^1=";
cout<<Squar(1,x,fun1)<<endl;
cout<<"(2x+3)^2=";
cout<<Squar(2,x,fun2)<<endl;
cout<<"(x^2+1)^3=";
cout<<Squar(3,x,fun3)<<endl;
cout<<endl;
return 0;
}