C++ to achieve the push box
- 2020-11-25 07:25:40
- OfStack
Example of this article for you to share C++ implementation of the box push game specific code, for your reference, the specific content is as follows
// 1.cpp : This file contains "main" Function. This is where program execution begins and ends.
//
#include <iostream>
#include <stdio.h>// s
#include <cstdlib>
#include <conio.h>
using std::cout;
const int row = 12;
const int col = 13;
int x = 1;
int y = 11;
int map[row][col] = {
{2,2,2,2,2,2,2,2,2,2,2,2,2},
{2,0,0,0,0,0,0,0,0,0,0,5,2},
{2,0,0,0,0,0,0,0,0,0,3,0,2},
{2,0,0,0,0,0,0,0,0,0,0,0,2},
{2,0,0,0,0,0,0,0,1,0,0,0,2},
{2,0,0,0,0,0,0,0,0,0,0,0,2},
{2,0,0,0,0,0,0,0,0,0,0,0,2},
{2,0,0,0,0,0,0,0,0,0,0,0,2},
{2,0,0,0,0,0,0,0,0,0,0,0,2},
{2,0,0,0,0,0,0,0,0,0,0,0,2},
{2,0,0,0,0,0,0,0,0,0,0,0,2},
{2,2,2,2,2,2,2,2,2,2,2,2,2},
};
void draw() {
int i;
for (i = 0; i < 12; i++)
{
for (int j = 0; j < 13; j++)
{
switch (map[i][j])
{
case 0:
{
cout << " ";//0 Stands for space that can be walked
break;
}
case 1:
{
cout << " u ";//1 P is for box, I'll just replace it with u
break;
}
case 2:
{
cout << " s ";//2 It represents a wall that cannot be crossed
break;
}
case 3:
{
cout << " Do things ";
break;
}
case 5:
{
cout << " ♀ ";//5 It's a person. It's mobile
break;
}
}
}
cout << "\n";
}
}
void move(int _x, int _y) {
if (map[x + _x][y + _y] == 2 || map[x + _x][y + _y] == 3 ||
map[x + _x][y + _y] == 5) {// Judge the boundary man can't walk out of the wall
return;
}
if (map[x + _x][y + _y] == 1) {
if (map[x + 2 * _x][y + 2 * _y] == 2) {
return;
}
map[x + _x][y + _y] = 0;
map[x + 2 * _x][y + 2 * _y] = 1;
move(_x, _y);
return;
}
map[x][y] = 0;
x += _x;
y += _y;
map[x][y] = 5;
draw();
}
void step(char o) {
switch (o) {
case 'w': {// Just like cf . cs In that way, wsad It's up, down, left, right
move(-1, 0);
break;
}
case 's': {
move(1, 0);
break;
}
case 'd': {
move(0, 1);
break;
}
case 'a': {
move(0, -1);
break;
}
}
}
int main()
{
while (true) {
draw();// According to the 2 Dimension array values to draw
step(_getch());// Get screen input directly
system("cls");// Clear the screen for animation
}
}Again for everyone to share 1 implementation code: thank the original author to share
Pushing box is a classic c + + title, use w a, s, d move, the effect from
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
int i,j;
void draw_map(int map[10][12]); // Declares the drawing function
int main()
{
system("title Li Baiheng ");
char input;
int count=0; // Define the score variable
int map[10][12] = {{2,2,2,2,2,1,1,1,1,1,2,2},
{1,1,1,1,2,1,0,0,0,1,1,2},
{1,0,0,1,1,1,0,1,0,0,1,2},
{1,0,4,3,3,3,3,3,1,0,1,1},
{1,0,0,1,1,3,3,3,4,0,0,1},
{1,0,0,0,0,4,1,1,4,1,0,1},
{1,0,4,1,4,0,0,0,4,0,0,1},
{1,1,0,6,0,1,1,1,4,1,0,1},
{2,1,1,1,1,1,2,1,0,0,0,1},
{2,2,2,2,2,2,2,1,1,1,1,1}
};
while (1) // Loop endlessly, waiting for user commands
{
system("CLS");
for (i=0;i<12;i++)
{
printf("%d",i);
}
printf("\n");
/*for (i=1;i<10;i++)
{
printf("%d\n",i);
}*/
printf("\n");
draw_map(map);
printf(" Current score: %d\n",count);
// Find the initial position
for (i=0;i<10;i++)
{
for (j=0;j<12;j++)
{
if (map[i][j]==6||map[i][j]==9)
break;
}
if (map[i][j]==6||map[i][j]==9)
break;
}
printf(" Your current coordinates ( %d . %d ) ",i,j);
input = getch(); // with getch() The function takes user input without carriage return confirmation and controls the direction of travel.
switch (input)
{
case 'w':
// If the person is in front of the open space. //0 On behalf of the clearing 6 representative //3 Representative destination
if(map[i-1][j]==0)
{
map[i-1][j]=6+0; // People walk 1 Step, ID human ID () plus open space ID ().
if(map[i][j]==9) // If the current location is the destination, then ID Of or relating to a person ID () plus destination ID ()).
map[i][j]=3; // He will go forward 1 After the step is in place ID Change to open space ID ().
else
map[i][j]=0; // Otherwise the in situ ID Change to open space ID .
}
// If the person in front is the destination.
else if((map[i-1][j]==3)||(map[i-1][j]==9))
{
map[i-1][j]=6+3; // People walk 1 Step, ID a ID+ destination ID=9 .
if(map[i][j]==9) // If the place is also the destination ( ID For).
map[i][j]=3; // People leave the place behind ID Modify back to destination ID .
else
map[i][j]=0; // Otherwise the in situ ID Change to open space ID
}
// If the person is in front of the box. //4 On behalf of the box //7 Box entry destination
else if(map[i-1][j]==4)
{
// If the person in front is a box, and the box in front is an empty space.
if (map[i-2][j]==0)
{
map[i-2][j]=4; // The man pushed the box forward 1 Step, put the open space ID Change to box ID (a)
// Here is the judgement of the box in situ
if(map[i-1][j]==7) // If the box is in place as the destination.
map[i-1][j]=9; // People stand where the box is (destination) ID Ought to be human ID+ destination ID=9 .
else
map[i-1][j]=6; // Otherwise, people are standing in the empty space, ID Should be +0=6 .
// Here's a look at where people are
if(map[i][j]==9) // If it was the destination before.
map[i][j]=3; // After the person leaves, modify to return to the destination ID .
else
map[i][j]=0; // Otherwise, it's empty space.
}
// If the front of the person is the box and the front of the box is the destination.
else if (map[i-2][j]==3)
{
map[i-2][j]=7; //ID Be the destination of ID (a) + The box ID (a) =7 "Has pushed the box to its destination.
count++;
// The following is the judgment of the original position of the box, ibid.
if(map[i-1][j]==7)
map[i-1][j]=9;
else
map[i-1][j]=6;
// The following is to judge the original position of the person, ditto.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
}
// If the person is in front of a box that has entered a destination ( ID=7 ).
else if(map[i-1][j]==7)
{
// If the person is in front of a box that has entered a destination , And the front of the box is empty space.
if(map[i-2][j]==0)
{
count--;
map[i-2][j]=4; // Push the box back into the open space, ID= The box ID+ clearing ID=4 .
map[i-1][j]=9; // People naturally stand on the original purpose of the ground.
// The following is the judgment of the original people, the same as above.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
// If the person is in front of a box that has entered a destination, and the box is in front of another box 1 The destination.
if(map[i-2][j]==3)
{
map[i-2][j]=7; // Pushed the box into the other 1 Destination, nature, ID Should also be.
map[i-1][j]=9; // Man stood on the spot.
// The following is the judgment of the original standing ground, the method is the same as above.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
}
break;
case 's':
// If the person is in front of the open space.
if(map[i+1][j]==0)
{
map[i+1][j]=6+0; // People walk 1 Step, ID human ID () plus open space ID ().
if(map[i][j]==9) // If the current location is the destination, then ID Of or relating to a person ID () plus destination ID ()).
map[i][j]=3; // He will go forward 1 After the step is in place ID Change to open space ID ().
else
map[i][j]=0; // Otherwise the in situ ID Change to open space ID .
}
// If the person in front is the destination.
else if(map[i+1][j]==3)
{
map[i+1][j]=6+3; // People walk 1 Step, ID a ID+ destination ID=9 .
if(map[i][j]==9) // If the place is also the destination ( ID For).
map[i][j]=3; // People leave the place behind ID Modify back to destination ID .
else
map[i][j]=0; // Otherwise the in situ ID Change to open space ID
}
// If the person is in front of the box.
else if(map[i+1][j]==4)
{
// If the person in front is a box, and the box in front is an empty space.
if (map[i+2][j]==0)
{
map[i+2][j]=4; // The man pushed the box forward 1 Step, put the open space ID Change to box ID (a)
// Here is the judgement of the box in situ
if(map[i+1][j]==7) // If the box is in place as the destination.
map[i+1][j]=9; // People stand where the box is (destination) ID Ought to be human ID+ destination ID=9 .
else
map[i+1][j]=6; // Otherwise, people are standing in the empty space, ID Should be +0=6 .
// Here's a look at where people are
if(map[i][j]==9) // If it was the destination before.
map[i][j]=3; // After the person leaves, modify to return to the destination ID .
else
map[i][j]=0; // Otherwise, it's empty space.
}
// If the front of the person is the box and the front of the box is the destination.
else if (map[i+2][j]==3)
{
map[i-2][j]=7; //ID Be the destination of ID (a) + The box ID (a) =7 "Has pushed the box to its destination.
count++;
// The following is the judgment of the original position of the box, ibid.
if(map[i+1][j]==7)
map[i+1][j]=9;
else
map[i+1][j]=6;
// The following is to judge the original position of the person, ditto.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
}
// If the person is in front of a box that has entered a destination ( ID=7 ).
else if(map[i+1][j]==7)
{
// If the person is in front of a box that has entered a destination , And the front of the box is empty space.
if(map[i+2][j]==0)
{
count--;
map[i+2][j]=4; // Push the box back into the open space, ID= The box ID+ clearing ID=4 .
map[i+1][j]=9; // People naturally stand on the original purpose of the ground.
// The following is the judgment of the original people, the same as above.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
// If the person is in front of a box that has entered a destination, and the box is in front of another box 1 The destination.
if(map[i+2][j]==3)
{
map[i+2][j]=7; // Pushed the box into the other 1 Destination, nature, ID Should also be.
map[i+1][j]=9; // Man stood on the spot.
// The following is the judgment of the original standing ground, the method is the same as above.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
}
break;
case 'a':
// If the person is in front of the open space.
if(map[i][j-1]==0)
{
map[i][j-1]=6+0; // People walk 1 Step, ID human ID () plus open space ID ().
if(map[i][j]==9) // If the current location is the destination, then ID Of or relating to a person ID () plus destination ID ()).
map[i][j]=3; // He will go forward 1 After the step is in place ID Change to open space ID ().
else
map[i][j]=0; // Otherwise the in situ ID Change to open space ID .
}
// If the person in front is the destination.
else if(map[i][j-1]==3)
{
map[i][j-1]=6+3; // People walk 1 Step, ID a ID+ destination ID=9 .
if(map[i][j]==9) // If the place is also the destination ( ID For).
map[i][j]=3; // People leave the place behind ID Modify back to destination ID .
else
map[i][j]=0; // Otherwise the in situ ID Change to open space ID
}
// If the person is in front of the box.
else if(map[i][j-1]==4)
{
// If the person in front is a box, and the box in front is an empty space.
if (map[i][j-2]==0)
{
map[i][j-2]=4; // The man pushed the box forward 1 Step, put the open space ID Change to box ID (a)
// Here is the judgement of the box in situ
if(map[i][j-1]==7) // If the box is in place as the destination.
map[i][j-1]=9; // People stand where the box is (destination) ID Ought to be human ID+ destination ID=9 .
else
map[i][j-1]=6; // Otherwise, people are standing in the empty space, ID Should be +0=6 .
// Here's a look at where people are
if(map[i][j]==9) // If it was the destination before.
map[i][j]=3; // After the person leaves, modify to return to the destination ID .
else
map[i][j]=0; // Otherwise, it's empty space.
}
// If the front of the person is the box and the front of the box is the destination.
else if (map[i][j-2]==3)
{
count++;
map[i][j-2]=7; //ID Be the destination of ID (a) + The box ID (a) =7 "Has pushed the box to its destination.
// The following is the judgment of the original position of the box, ibid.
if(map[i][j-1]==7)
map[i][j-1]=9;
else
map[i][j-1]=6;
// The following is to judge the original position of the person, ditto.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
}
// If the person is in front of a box that has entered a destination ( ID=7 ).
else if(map[i][j-1]==7)
{
// If the person is in front of a box that has entered a destination , And the front of the box is empty space.
if(map[i][j-2]==0)
{
count--;
map[i][j-2]=4; // Push the box back into the open space, ID= The box ID+ clearing ID=4 .
map[i][j-1]=9; // People naturally stand on the original purpose of the ground.
// The following is the judgment of the original people, the same as above.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
// If the person is in front of a box that has entered a destination, and the box is in front of another box 1 The destination.
if(map[i][j-2]==3)
{
map[i][j-2]=7; // Pushed the box into the other 1 Destination, nature, ID Should also be.
map[i][j-1]=9; // Man stood on the spot.
// The following is the judgment of the original standing ground, the method is the same as above.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
}
break;
case 'd':
// If the person is in front of the open space.
if(map[i][j+1]==0)
{
map[i][j+1]=6+0; // People walk 1 Step, ID human ID () plus open space ID ().
if(map[i][j]==9) // If the current location is the destination, then ID Of or relating to a person ID () plus destination ID ()).
map[i][j]=3; // He will go forward 1 After the step is in place ID Change to open space ID ().
else
map[i][j]=0; // Otherwise the in situ ID Change to open space ID .
}
// If the person in front is the destination.
else if(map[i][j+1]==3)
{
map[i][j+1]=6+3; // People walk 1 Step, ID a ID+ destination ID=9 .
if(map[i][j]==9) // If the place is also the destination ( ID For).
map[i][j]=3; // People leave the place behind ID Modify back to destination ID .
else
map[i][j]=0; // Otherwise the in situ ID Change to open space ID
}
// If the person is in front of the box.
else if(map[i][j+1]==4)
{
// If the person in front is a box, and the box in front is an empty space.
if (map[i][j+2]==0)
{
map[i][j+2]=4; // The man pushed the box forward 1 Step, put the open space ID Change to box ID (a)
// Here is the judgement of the box in situ
if(map[i][j+1]==7) // If the box is in place as the destination.
map[i][j+1]=9; // People stand where the box is (destination) ID Ought to be human ID+ destination ID=9 .
else
map[i][j+1]=6; // Otherwise, people are standing in the empty space, ID Should be +0=6 .
// Here's a look at where people are
if(map[i][j]==9) // If it was the destination before.
map[i][j]=3; // After the person leaves, modify to return to the destination ID .
else
map[i][j]=0; // Otherwise, it's empty space.
}
// If the front of the person is the box and the front of the box is the destination.
else if (map[i][j+2]==3)
{
count++;
map[i][j+2]=7; //ID Be the destination of ID (a) + The box ID (a) =7 "Has pushed the box to its destination.
// The following is the judgment of the original position of the box, ibid.
if(map[i][j+1]==7)
map[i][j+1]=9;
else
map[i][j+1]=6;
// The following is to judge the original position of the person, ditto.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
}
// If the person is in front of a box that has entered a destination ( ID=7 ).
else if(map[i][j+1]==7)
{
// If the person is in front of a box that has entered a destination , And the front of the box is empty space.
if(map[i][j+2]==0)
{
count--;
map[i][j+2]=4; // Push the box back into the open space, ID= The box ID+ clearing ID=4 .
map[i][j+1]=9; // People naturally stand on the original purpose of the ground.
// The following is the judgment of the original people, the same as above.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
// If the person is in front of a box that has entered a destination, and the box is in front of another box 1 The destination.
if(map[i][j+2]==3)
{
map[i][j+2]=7; // Pushed the box into the other 1 Destination, nature, ID Should also be.
map[i][j+1]=9; // Man stood on the spot.
// The following is the judgment of the original standing ground, the method is the same as above.
if(map[i][j]==9)
map[i][j]=3;
else
map[i][j]=0;
}
}
break;
}
if(count==8) // If the score reaches a score
{
system("CLS"); // Clear the screen
draw_map(map);
break; // Exit loop
}
}
printf("\n Congratulations, you passed!! \n"); // With prompt
return 0;
}
void draw_map(int map[10][12])
{
for(i=0;i<10;i++)
{
for(j=0;j<12;j++)
{
switch(map[i][j])
{
case 0:
printf(" "); // The number is the road
break;
case 1:
printf("#"); // The Numbers are the walls
break;
case 2:
printf(" "); // The Numbers are the margins of the borders of the game
break;
case 3:
printf("!"); // The number represents the destination
break;
case 4:
printf("*"); // The number is the box
break;
case 7:
printf("$"); // The number represents the box entering the destination
break;
case 6:
printf("@"); // Digital representative
break;
case 9:
printf("@"); // The number represents the entry destination
break;
}
}
printf("\n"); // The branch output
}
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