C language code to implement 2048 game
- 2020-06-23 01:39:38
- OfStack
I am a freshman in college. In the winter vacation training class, the teacher asked us to program a small game with c language in groups, and our group selected "2048". Due to our group have a great god, and we do most of the work to the great god, but I feel useless after training completed, learn nothing, their understanding of the c language is limited to books, can think of the great god have basic programming 1 small game, the in the mind is very worried. So this winter vacation, I independently completed the "2048" game programming.
I wrote the game code with Xcode, and I am IOS white. Some header files cannot be used in Xcode and I cannot find a substitute. Therefore, some functions cannot be realized, such as screen clearing function, data storage function and music function. I hope to have a great god can guide me, very grateful!
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<curses.h>
/* The header file */
int i,j,a[4][4]={};/*2 Dimensional array a[4][4] For all 0*/
void kaishi()/* Generate start interface */
{
printf("Welcome to 2048\n");
printf(" 1). A new game \n");
printf(" 2). help \n");
}
int defen(int a[][4])/* The scoring function */
{
int max=a[0][0];
int static sum=0;
for(i=0;i<4;i++)
for(j=0;j<4;j++)
if(a[i][j]>max)
max=a[i][j];
sum+=max;
return sum;/* Take the sum of the largest number as the score */
}
void jiemian(int a[][4])
{
int b[2]={2,4},c[4]={0,1,2,3},sum,n,m;
do
{
srand((int)time(NULL));/* Take time as a random number seed */
m=c[rand()%4];
n=c[rand()%4];
/* Randomly generated coordinates */
if(a[m][n]==0)/* Determines whether it is a space */
{
a[m][n]=b[rand()%2];/* Randomly generated 2 or 4*/
break;/* Jump out of the loop */
}
}while(1);
printf("%d %d %d\n",m,n,a[m][n]);
for(i=0;i<4;i++)
{
printf("-------------------------\n");
for(j=0;j<4;j++)
{
if((m==i)&&(n==j))
printf("| %d ",a[m][n]);/* The output is randomly generated 2 or 4*/
else
{
if(a[i][j]>0)
printf("| %d ",a[i][j]);/* if a[i][j] If there are Numbers, output them */
else
printf("| ");/* if a[i][j] No Numbers, output Spaces */
}
}
printf("|\n");
}
printf("-------------------------\n");
printf(" score :%d\n",sum=defen(a));
}
void hebingup(int a[][4])/* Up to merge */
{
int m;
for(j=0;j<4;j++)
for(i=0;i<3;i++)
if(a[i][j]>0)/* if a[i][j] Don't for 0 Judge, otherwise jump straight down 1 item */
if(a[i][j]==a[i+1][j]&&a[i][j]!=0)/* To determine whether two adjacent terms are equal */
{
a[i][j]=2*a[i][j];/* The above 1 This term is going to double */
if(i==2)
a[i+1][j]=0;
else
for(m=i+1;m<3;m++)
{
a[m][j]=a[m+1][j];
a[m+1][j]=0;
}
/* Move the following Numbers up as a whole and recycle */
}
}
void hebingdown(int a[][4])/* Merge down */
{
int m;
for(j=0;j<4;j++)
for(i=3;i>0;i--)
if(a[i][j]>0)
if(a[i][j]==a[i-1][j])
{
a[i][j]=2*a[i][j];
if(i==1)
a[i-1][j]=0;
else
for(m=i-1;m>0;m--)
{
a[m][j]=a[m-1][j];
a[m-1][j]=0;
}
}
}
void hebingleft(int a[][4])/* To the left to merge */
{
int m;
for(i=0;i<4;i++)
for(j=0;j<3;j++)
if(a[i][j]>0)
if(a[i][j]==a[i][j+1])
{
a[i][j]=2*a[i][j];
if(j==2)
a[i][j+1]=0;
else
for(m=j+1;m<3;m++)
{
a[i][m]=a[i][m+1];
a[i][m+1]=0;
}
}
}
void hebingright(int a[][4])/* Merge to the right */
{
int m;
for(i=0;i<4;i++)
for(j=3;j>0;j--)
if(a[i][j]>0)
if(a[i][j]==a[i][j-1])
{
a[i][j]=2*a[i][j];
if(j==1)
a[i][j-1]=0;
else
for(m=j-1;m>0;m--)
{
a[i][m]=a[i][m-1];
a[i][m-1]=0;
}
}
}
void yidong(char b)
{
int x,m;
switch(b)
{
case 'w' :
for(j=0;j<4;j++)
for(i=1;i<=3;i++)
for(x=i,m=i;x>0;x--,m--)/*x Is the number of cycles, m alternative i Keep the cycle going */
{
if(a[m-1][j]>0)
break;/* If the 1 A non 0 And jump down 1 position */
else
{
a[m-1][j]=a[m][j];
a[m][j]=0;
}
}
hebingup(a);
break;
case 's' :
for(j=0;j<4;j++)
for(i=2;i>=0;i--)
for(x=3-i,m=i;x>0;x--,m++)
{
if(a[m+1][j]>0)
break;
else
{
a[m+1][j]=a[m][j];
a[m][j]=0;
}
}
hebingdown(a);
break;
case 'a' :
for(i=0;i<4;i++)
for(j=1;j<=3;j++)
for(x=j,m=j;x>0;x--,m--)
{
if(a[i][m-1]>0)
break;
else
{
a[i][m-1]=a[i][m];
a[i][m]=0;
}
}
hebingleft(a);
break;
case 'd' :
for(i=0;i<4;i++)
for(j=2;j>=0;j--)
for(x=3-j,m=j;x>0;x--,m++)
{
if(a[i][m+1]>0)
break;
else
{
a[i][m+1]=a[i][m];
a[i][m]=0;
}
}
hebingright(a);
break;
}
}
int main(int argc,char *argv[])
{
int flag=1;
char c,k;
system("stty -icanon");
outloop:;
kaishi();
k=getchar();
printf("\n");
if(k=='1')
{
while(flag==1)
{
jiemian(a);
c=getchar();
printf("\n");
yidong(c);
for(i=0;i<4;i++)
for(j=0;j<4;j++)
{
if(a[i][j]==0)
{
flag=1;
goto end;/* If you have a checkerboard 1 Jump out of the judgment and continue to generate random Numbers */
}
else
flag=0;
}
end:;
}
}
if(k=='2')
{
do
{
printf(" Rules of the game: by clicking <w>,<s>,<a>,<d> Key to move the Numbers up, down, left and right. Add the same Numbers. The sum of the Numbers in each cell will be scored. \n");
printf(" 3). return \n");
k=getchar();
}while(k!=3);
goto outloop;/* Jump to the start screen */
}
printf(" Game over \n");
return 0;
}