The C language implementation reads a 3 by 3 array from a file and calculates the average of each row

Topic request

Read a 3 by 3 array from the file and calculate the average of each row.

The reference solution

1. Data file: ES7en.dat

Create 1.dat file to hold the array file:

1    3    6
2    9    7
3    6    4

The file name is arbitrary.

Code 2.

avg = (a[i][0] + a[i][1] + a[i][2]) / 3 if the row average is calculated. This line of code will do.

Too easy to bother to write method:

#include<stdio.h>

void main(){
 FILE *fr;
 int i, j, a[3][3];
 float avg;
 fr = fopen("array.dat", "r");

 while(!feof(fr))
 {
 printf("Command successfully executed.\n");
 for(i=0; i<3; i++)
  for(j=0; j<3; j++)
  fscanf(fr, "%d", &a[i][j]);
 }

 printf(" The array read in is: \n");
 for(i=0; i<3; i++)
 for(j=0; j<3; j++){
  printf("%d\t", a[i][j]);
  if(j == 2)
  printf("\n");
 }

 printf("\n The average of the array rows is: \n");
 for(i=0; i<3; i++){
 printf(" The first %d The average of the rows is: ", i+1);
 avg = (a[i][0] + a[i][1] + a[i][2]) / 3;
 printf("%.2f\n", avg);
 }
}