# C language beginner's basic tutorial judgment

• 2020-05-30 20:50:38
• OfStack

(1)

Write a program first:

``````
#include <stdio.h>

int main()
{
if(1)
{
printf("The condition is true!\n");
}

return 0;
}

``````

Operation results:

`The condition is true!`

Then I changed the 1 to 2,5,100, -10, and found that the result was exactly the same.
If I change it to if(0), I will find that there is no result, indicating that the printf() statement has not been executed.

The C language takes as true any non-zero or non-null value in the judgment statement. So if(1), if(2), if(5), if(100), if(-10) have the same effect.

(2)

Write another program:

``````
#include <stdio.h>

int main()
{
int a = 100;
if(a > 0)
{
printf("The condition value is %d\n", (a > 0));
}

return 0;
}

``````

Operation results:

`The condition value is 1`

Analysis:
a = 100, a > 0 is true, so if(a) > 0) is the same thing as if of 1.
In C, the judgment statement has a value of either 1 or 0. For example, a in this program > The value of 0 is 1.

(3)

Finally, write a program:

``````
#include <stdio.h>

int main()
{
char c1 = '\0';
if(c1)
{
printf("The condition is true!\n");
}
else
{
printf("The condition is false!\n");
}

char c2 = ' ';
if(c2)
{
printf("The condition is true!\n");
}
else
{
printf("The condition is false!\n");
}

char c3 = 'A';
if(c3)
{
printf("The condition is true!\n");
}
else
{
printf("The condition is false!\n");
}

return 0;
}

``````

Operation results:

``````
The condition is false!
The condition is true!
The condition is true!
``````

Note: C USES '\0' to represent empty characters. The space ' 'is also one character, as you can see from the if(c2) condition that it is true.

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