An example of maze algorithm based on C language

This paper illustrates the maze algorithm based on C. I will share it with you for your reference as follows:

Maze algorithm using c language, environment is vc++6.0.

#include<stdio.h>
#include<time.h>
#include<cstdlib>
int visit(int,int);
void setmaze();
int maze[11][11]=
{
  {0,0,2,2,2,2,2,2,2,2},
  {2,0,2,2,0,2,0,2,0,2},
  {2,0,2,0,0,0,0,0,0,2},
  {2,0,2,2,2,0,2,0,0,2},
  {2,0,0,0,0,0,2,2,0,2},
  {2,2,0,2,2,0,2,2,0,2},
  {2,2,2,0,0,0,0,0,0,2},
  {2,0,2,0,2,0,2,2,0,2},
  {2,0,0,0,0,2,0,2,0,0},
  {2,2,2,2,2,2,2,2,2,2}
};
int startI,startJ; // Define entry variables 
int endI,endJ; // Define exit variables 
int success=0; // Define the return variable 
int p;
void setStart()    //  Set the entrance 
{
 printf(" Please set the maze entrance ( i,j ) :");
 scanf("%d,%d",&startI,&startJ);
}
void setEnd()    //  Set the export 
{
  printf(" Please set the maze exit ( i,j ) :");
  scanf("%d,%d",&endI,&endJ);
}
void setmaze()   // Set the maze diagram 
{
  int i,j,a,p;
  for(i=0;i<10;i++)
    for(j=0;j<10;j++)
    {
      p=rand()%2;
      if(p==0) a=0;
      else a=2;
      maze[i][j]=a;
    }
}
void DisplayMaze()    // Print a maze 
{
  int i,j;
  for(i=0;i<10;i++)
  {
  printf("  ");
  for(j=0;j<10;j++)
       if(maze[i][j]==2) printf("##");      // Print the wall 
        else printf(" ");        // Print the path 
     printf("/n");
   }
}
void Maze_PS()      // Output maze path 
{
  int i,j;
  if(visit(startI,startJ)==0) // Search path 
       printf("/n No way out! /n");
    else
    {
  maze[startI][startJ]=8;// Set up entrance marks 
      maze[endI][endJ]=9;// Set up exit marks 
       printf("/n Display path: /n");
       for(i=0;i<10;i++)
   {
        for(j=0;j<10;j++)
         {
    if(maze[i][j]==8) printf(" Do things ");// Marks the entrance 
     else if(maze[i][j]==9) printf(" a. ");// Mark export 
              else if(maze[i][j]==2)    printf("##"); // Said the wall 
               else if(maze[i][j]==1) printf(" >"); // Said path 
                  else  printf(" "); // pathways 
           }
           printf("/n");
       }
    }
}
int visit(int i,int j)  // Find the maze path function, find the path back 1 , could not find the path back 0
{
    maze[i][j]=1;
    if((i==endI)&&(j==endJ)) success=1; // Find the exit and return the value success for 1
    if((success!=1)&&(maze[i][j+1]==0)) visit(i,j+1); // Detect the right channel and move to the right if it is open 
    if((success!=1)&&(maze[i+1][j]==0)) visit(i+1,j); // Detect the following path, if it is open, move down 
    if((success!=1)&&(maze[i][j-1]==0)) visit(i,j-1); // Detect the left side of the path. If it is open, move to the left 
    if((success!=1)&&(maze[i-1][j]==0)) visit(i-1,j); // Detect the upper channel and move upward if it is open 
    if(success!=1) maze[i][j]=0; // Return and label itself as 0
    return success;
}
main(void)    // The main function 
{
   int c1,c2;
   for(c2=1;c2==1;)
   {
     srand(time(0));
     printf(" Show the maze: /n");
     for(c1=1;c1==1;)
     {
       DisplayMaze();
       printf(" According to the '1' Output new maze ,'2' Start solving path: /n");
       scanf("%d",&c1);
  rewind(stdin);// Clear input buffer 
       if(c1==1) setmaze() ;
     }
     if(c1!=1&&c1!=2) {printf("Error!!/n");break;}
     setStart();
     setEnd();
     Maze_PS();
     printf("Continue?(1 to continue,2 to exit.1)");
     scanf("%d",&c2);
     if(c2==1) setmaze();
     else break;
   }
   system("pause");
}

I hope this article has been helpful to you in the programming of C language.